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aniked [119]
3 years ago
13

There are Z protons in the nucleus of an atom, where Z is the atomic number of the element. An α particle carries a charge of +2

e. In a scattering experiment, an α particle, heading directly toward a nucleus in a metal foil, will come to a halt when all of the particle's kinetic energy is converted to electric potential energy. In such a situation, how close will the center of an α particle with a kinetic energy of 6.4 x 10-13 J come to the center of a gold nucleus (Z = 79)?
Physics
1 answer:
qaws [65]3 years ago
7 0

Answer:

r = 2.84 \times 10^{-14} m

Explanation:

As per energy conservation we know that the electrostatic potential energy of the charge system is equal to the initial kinetic energy of the alpha particle

So here we can write it as

\frac{1}{2}mv^2 = \frac{k(2e)(ze)}{r}

now we know that

m = 1.67 \times 10^{-27} kg

e = 1.6 \times 10^{-19} C

z = 79

here kinetic energy of the incident alpha particle is given as

KE = 6.4 \times 10^{-13} J

now we have

6.4 \times 10^{-13} = \frac{(9\times 10^9)(1.6 \times 10^{-19})^2(79)}{r}

now we have

r = 2.84 \times 10^{-14} m

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Answer:

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3. A coil of 100 turns encloses an area of 100 cm2. It is placed at an angle of 700 with a
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Explanation:

Given that,

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We need to find the magnetic flux through the coil and the emf is induced in the coil after 10⁻³ s.

Magnetic flux is given by :

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So, the magnetic flux through the coil is 0.1 Wb.

Emf induced in the coil is :

\epsilon=\dfrac{-d\phi}{dt}\\\\=\dfrac{0.034}{10^{-3}}\\\\=34\ V

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3 years ago
How many signifficant figures do the following number have 258​
Romashka [77]

Answer:

<u>Facts about 258</u>

<u>Sig Figs</u>

3

<u>258</u>

<u>Decimals</u>

0

<u>Scientific Notation</u>

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<u>E-Notation</u>

2.58e+2

<u>Words</u>

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Explanation:

258 Rounded to Fewer Sig Figs

2 260                2.6 × 102

1 300           3 × 102

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