Answer: a = 1.32 * 10^18m/s² due north
Explanation: The magnitude of the force required to move the electron is given as
F = ma
The force exerted on the charge by the electric field of intensity (E) is given by
F = Eq
Thus
Eq = ma
a = E * q/ m
Where a = acceleration of charge
E = strength of electric field = 7400N/c
q = magnitude of electronic charge = 1.609 * 10^-6c
m = mass of an electronic charge = 9.109 * 10^-31kg
a = 7400 * 1.609 * 10^-16/ 9.109 * 10^-31
a = 11906.6 * 10^-16 / 9.019 * 10^-31
a = 1.19 * 10^-12 / 9.019 * 10^-31
a = 0.132 * 10^19
a = 1.32 * 10^18m/s²
As stated in the question, the direction of the electric field is due north hence, the direction of it force will also be north thus making the electron experience a force due north ( according to Newton second law of motion)
Answer:
Meter
Explanation:
I'd say meters, cause it's the SI unit of length,
which is a Derived Quantity.
Answer: R = 346.4N and angle 30° to the horizontal negative axis
Explanation:
To find the resultant force, we need to sum up the forces on the vertical and horizontal axis.
For the horizontal axis;
Rx = -b + acos60
Rx = -400N +200cos60
Rx = -400N +100N
Rx = -300N
For the vertical axis;
Ry = asin60 = 200sin60
Ry = 173.2N
The resultant force R can be given as;
R = √(Rx^2 +Ry^2)
R = √((-300)^2 + 173.2^2)
R = 346.4N
Angle z can be written as
Tanz = Ry/Rx
z = taninverse (Ry/Rx)
z = taninverse (173.2/300)
z = 30°
I believe that would be 1,080,000,000 Kilometers per hour- lmk if that helps
The first A.C. system in the United States was built by
B. Michael Faraday
