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Vinvika [58]
3 years ago
10

Quadrilateral MNOP is reflected over a line and translated up, as shown.

Mathematics
1 answer:
tia_tia [17]3 years ago
7 0

Answer: its 130 degrees

Step-by-step explanation: if you reflect it over the line and translate it up a little to be on top of the other image it will be the same and have 130 degrees in the same spot

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What are the x and y-intercepts of the line described by this equation? -6x+3y=18.9?
Naddika [18.5K]

The "x" intercept is found when you plug in "0" for "y"
  -6x + 3(0) = 18.9
        -6x = 18.9  (Divide both sides by -6)
           x = - 3.15
           (-3.15, 0)  is your x-intercept

Now plug in "0" for the x
-6(0) + 3y = 18.9
          3y = 18.9  (Divide both sides by 3)
                y = 6.3
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5 0
4 years ago
Evaluate 3r³+5,when r=2
Elza [17]

Answer:

29  

Step-by-step explanation:

8 0
3 years ago
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Whats is the diference of:
grandymaker [24]

Answer:

2h^2

Step-by-step explanation:

=> (10h^4+h^2)-(10h^4-h^2)

=> 10h^4+h^2-10h^4+h^2

=> h^2+h^2

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7 0
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Solve for y<br> 8x + y = 32
oksian1 [2.3K]

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8 0
3 years ago
Based on the information given say whether or not △ABC∼△FED. Explain your reasoning.
GalinKa [24]

Answer:

Yes, △ABC ∼ △FED by AA postulate.

Step-by-step explanation:

Given:

Two triangles ABC and FED.

m∠A = m∠B

m∠C = m∠A + 30°

m∠E = m∠F = x

m∠D = 2x-20°.

Now, let m∠A = m∠B = y

So, m∠C = m∠A + 30° = y+30

Now, sum of all interior angles of a triangle is 180°. Therefore,

m∠A + m∠B +  m∠C = 180

y+y+y+30=180\\3y=180-30\\3y=150\\y=\frac{150}{3}=50

Therefore, m∠A = 50°, m∠B = 50° and m∠C =  m∠A + 30° = 50 + 30 = 80°.

Now, consider triangle FED,

m∠D+ m∠E + m∠F = 180

2x-20+x+x=180\\4x=180+20\\4x=200\\x=\frac{200}{4}=50

Therefore,  m∠F = 50°  

m∠E = 50° and  

m∠D =  2x-20=2(50)-20=100-20=80\°

So, both the triangles have congruent corresponding angle measures.

m∠A = m∠F = 50°

m∠B = m∠E = 50°

m∠C = m∠D = 80°

Therefore, the two triangles are similar by AA postulate.

5 0
3 years ago
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