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drek231 [11]
3 years ago
9

What is the GCF for 28 and 70

Mathematics
2 answers:
Delicious77 [7]3 years ago
8 0
28. 4,7,28

70. 7,10,70,
 
7 is GCF 
aliya0001 [1]3 years ago
3 0
The factors of 28 are 1, 2, 4, 7, 14, and 28. 
<span>The factors of 70 are 1, 2, 5, 7, 10, 14, 35, and 70. </span>
<span>The common factors are 1, 2, 7, and 14. Therefore, the greatest common factor is 14. </span>
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What multiplies to give you 108 and adds up to give you -31?
meriva
4 x 27  = 108 and 4 + 27 = 31... I don't think there is any pair of numbers that would equal -31. So the answer would be 4 and 27. Good luck! Hope this helped!!
4 0
3 years ago
(Answer with Explanation. I will mark BRAINLIEST! 100 pts.)
katovenus [111]

Answer:

lemme answer it,I'll put the answer at the comment section

8 0
3 years ago
If(x) = x + 2 and h(x) = x-1, what is f • h](-3)?
deff fn [24]

Answer/Step-by-step explanation:

Composition functions are functions that combine to make a new function. We use the notation ◦ to denote a composition.

f ◦ g is the composition function that has f composed with g. Be aware though, f ◦ g is not

the same as g ◦ f. (This means that composition is not commutative).

f ◦ g ◦ h is the composition that composes f with g with h.

Since when we combine functions in composition to make a new function, sometimes we

define a function to be the composition of two smaller function. For instance,

h = f ◦ g (1)

h is the function that is made from f composed with g.

For regular functions such as, say:

f(x) = 3x

2 + 2x + 1 (2)

What do we end up doing with this function? All we do is plug in various values of x into

the function because that’s what the function accepts as inputs. So we would have different

outputs for each input:

f(−2) = 3(−2)2 + 2(−2) + 1 = 12 − 4 + 1 = 9 (3)

f(0) = 3(0)2 + 2(0) + 1 = 1 (4)

f(2) = 3(2)2 + 2(2) + 1 = 12 + 4 + 1 = 17 (5)

When composing functions we do the same thing but instead of plugging in numbers we are

plugging in whole functions. For example let’s look at the following problems below:

Examples

• Find (f ◦ g)(x) for f and g below.

f(x) = 3x + 4 (6)

g(x) = x

2 +

1

x

(7)

When composing functions we always read from right to left. So, first, we will plug x

into g (which is already done) and then g into f. What this means, is that wherever we

see an x in f we will plug in g. That is, g acts as our new variable and we have f(g(x)).

g(x) = x

2 +

1

x

(8)

f(x) = 3x + 4 (9)

f( ) = 3( ) + 4 (10)

f(g(x)) = 3(g(x)) + 4 (11)

f(x

2 +

1

x

) = 3(x

2 +

1

x

) + 4 (12)

f(x

2 +

1

x

) = 3x

2 +

3

x

+ 4 (13)

Thus, (f ◦ g)(x) = f(g(x)) = 3x

2 +

3

x + 4.

Let’s try one more composition but this time with 3 functions. It’ll be exactly the same but

with one extra step.

• Find (f ◦ g ◦ h)(x) given f, g, and h below.

f(x) = 2x (14)

g(x) = x

2 + 2x (15)

h(x) = 2x (16)

(17)

We wish to find f(g(h(x))). We will first find g(h(x)).

h(x) = 2x (18)

g( ) = ( )2 + 2( ) (19)

g(h(x)) = (h(x))2 + 2(h(x)) (20)

g(2x) = (2x)

2 + 2(2x) (21)

g(2x) = 4x

2 + 4x (22)

Thus g(h(x)) = 4x

2 + 4x. We now wish to find f(g(h(x))).

g(h(x)) = 4x

2 + 4x (23)

f( ) = 2( ) (24)

f(g(h(x))) = 2(g(h(x))) (25)

f(4x

2 + 4x) = 2(4x

2 + 4x) (26)

f(4x

2 + 4x) = 8x

2 + 8x (27)

(28)

Thus (f ◦ g ◦ h)(x) = f(g(h(x))) = 8x

2 + 8x.

4 0
3 years ago
Zendaya has 5656 yard of wood to make racks for a word tile game. Each rack needs to be 1616 yard long. How many racks can Zenda
snow_lady [41]

Answer: 3

Step-by-step explanation:

Given

Zendaya has 5656 yards of wood

Each rack need 1616 yards

Number of racks that can be formed using 5656 yards are

\Rightarrow \dfrac{5656}{1616}=3.5

3.5 represents 3 racks as 0.5 racks is insignificant

Therefore, 3 racks can be built from 5656 yards

4 0
3 years ago
Let g(x)=3x+2 and f(x)= x-2/3
son4ous [18]

Answer:

1.) 1 1/3 or 4/3

2.) 6

3.) 8

Step-by-step explanation:

Function composition substitutes more than just values or constants. It substitutes functions inside another function. Solve each expression by starting inner most and working to outermost.

1.) f(g(0))  = 1 1/3

Let g(x)=3x+2 and f(x)= x-2/3.

Begin with g(0) = 3(0) + 2 = 2.

Substitute x = 2 into f(x).

f(2) = (2) - 2/3 = 1 1/3

2.) g(f(2))  = 6

Let g(x)=3x+2 and f(x)= x-2/3.

Begin with f(2) = 2 - 2/3 = 1 1/3.

Substitute x = 1 1/3 into g(x).

g(1 1/3) = 3( 1 1/3) + 2 = 3(4/3) + 2 = 4 + 2 = 6

3.) g(g((0))

Let g(x)=3x+2.

Begin with g(0) = 3(0) + 2 = 2.

Substitute x = 2 into g(x).

g(2) = 3(2) + 2 = 8

7 0
4 years ago
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