We can rewrite the expression under the radical as
then taking the fourth root, we get
![\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cleft%28%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%29%5E4%7D%3D%5Cleft%7C%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%7C)
Why the absolute value? It's for the same reason that
since both 
and 
return the same number , and 
captures both possibilities. From here, we have
The absolute values disappear on all but the 
term because all of 
, 
and 
are positive, while 
could potentially be negative. So we end up with
Answer:
w > 7
Step-by-step explanation:
L = 3w
2L + 2w > 56
sub for L
2(3w) + 2w > 56
6w + 2w > 56
8w > 56
w > 7
Check: L = 3(8)
L = 24
2(24) + 2(8) > 56
48 + 16 > 56
64 > 56
Hello,
We have : (a + b)² = a² + 2ab + b²
4x² + 20x + 25 = (2x)² + 2 × 2x × 5 + 5² = (2x + 5)² → answer B
Here, we have a = 2x and b = 5 !
When a tangent line (13.5 cm) and a secant (lines x + 8.45 cm) intersect then:
tangent line^2 = 8.45 * (8.45 + x)
13.5^2 = 71.4025 + 8.45 x
182.25 -71.4025 = 8.45x
8.45 x = 110.8475
x = 13.1180473373
x = 13.1 (rounded)
Source:
1728.com/circangl.htm
Answer:
B. 16/3
Step-by-step explanation:
f(2) = 1/3 · 4²
f(2) = 1/3 · 16
f(2) = 16/3
