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seropon [69]
2 years ago
15

If(x) = x + 2 and h(x) = x-1, what is f • h](-3)?

Mathematics
1 answer:
deff fn [24]2 years ago
4 0

Answer/Step-by-step explanation:

Composition functions are functions that combine to make a new function. We use the notation ◦ to denote a composition.

f ◦ g is the composition function that has f composed with g. Be aware though, f ◦ g is not

the same as g ◦ f. (This means that composition is not commutative).

f ◦ g ◦ h is the composition that composes f with g with h.

Since when we combine functions in composition to make a new function, sometimes we

define a function to be the composition of two smaller function. For instance,

h = f ◦ g (1)

h is the function that is made from f composed with g.

For regular functions such as, say:

f(x) = 3x

2 + 2x + 1 (2)

What do we end up doing with this function? All we do is plug in various values of x into

the function because that’s what the function accepts as inputs. So we would have different

outputs for each input:

f(−2) = 3(−2)2 + 2(−2) + 1 = 12 − 4 + 1 = 9 (3)

f(0) = 3(0)2 + 2(0) + 1 = 1 (4)

f(2) = 3(2)2 + 2(2) + 1 = 12 + 4 + 1 = 17 (5)

When composing functions we do the same thing but instead of plugging in numbers we are

plugging in whole functions. For example let’s look at the following problems below:

Examples

• Find (f ◦ g)(x) for f and g below.

f(x) = 3x + 4 (6)

g(x) = x

2 +

1

x

(7)

When composing functions we always read from right to left. So, first, we will plug x

into g (which is already done) and then g into f. What this means, is that wherever we

see an x in f we will plug in g. That is, g acts as our new variable and we have f(g(x)).

g(x) = x

2 +

1

x

(8)

f(x) = 3x + 4 (9)

f( ) = 3( ) + 4 (10)

f(g(x)) = 3(g(x)) + 4 (11)

f(x

2 +

1

x

) = 3(x

2 +

1

x

) + 4 (12)

f(x

2 +

1

x

) = 3x

2 +

3

x

+ 4 (13)

Thus, (f ◦ g)(x) = f(g(x)) = 3x

2 +

3

x + 4.

Let’s try one more composition but this time with 3 functions. It’ll be exactly the same but

with one extra step.

• Find (f ◦ g ◦ h)(x) given f, g, and h below.

f(x) = 2x (14)

g(x) = x

2 + 2x (15)

h(x) = 2x (16)

(17)

We wish to find f(g(h(x))). We will first find g(h(x)).

h(x) = 2x (18)

g( ) = ( )2 + 2( ) (19)

g(h(x)) = (h(x))2 + 2(h(x)) (20)

g(2x) = (2x)

2 + 2(2x) (21)

g(2x) = 4x

2 + 4x (22)

Thus g(h(x)) = 4x

2 + 4x. We now wish to find f(g(h(x))).

g(h(x)) = 4x

2 + 4x (23)

f( ) = 2( ) (24)

f(g(h(x))) = 2(g(h(x))) (25)

f(4x

2 + 4x) = 2(4x

2 + 4x) (26)

f(4x

2 + 4x) = 8x

2 + 8x (27)

(28)

Thus (f ◦ g ◦ h)(x) = f(g(h(x))) = 8x

2 + 8x.

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coldgirl [10]

Step-by-step explanation:

If y is largest number, you want y, and the two next smaller even integers smaller than y - i.e. y, y-2, and y-4

The sum of these is y + (y-2) + (y-4).

This simplifies to 3y - 6 or 3(y - 2)

Since we don’t know what y is, this is as far as we can solve the problem.

6 0
2 years ago
Find the domain of the following piecewise function.
il63 [147K]

Answer:

(2,8]

Step-by-step explanation:

Given

The attached piece wise function

Required

The domain

To do this, we simply consider the inequalities that bound the values of x.

The inequalities are:

2 < x < 4     4 < x < 8   and   x \ge 8

Combine the first two inequalities:

2 < x < 8    and   x \ge 8

For the inequality to be true, we must have:

2 < x \le 8

In interval notation, the inequality is:

(2,8]

6 0
2 years ago
2b to the power of 2 = 100 i want to know if this question is true or false, someone help me pleaseee.
OLEGan [10]

Answer

5

Step-by-step explanation:

10^2= 100

so b must be 5

6 0
2 years ago
SinA=√1-x÷√1+X<br> Find the value of cosA
Irina-Kira [14]

The value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

<h3>Trigonometric ratios</h3>

It is important to note that

sin A = opposite/ hypotenuse

cos A = adjacent/ hypotenuse

Then,

opposite = \sqrt{1} - x

Hypotenuse = \sqrt{1} + x

Let's find the adjacent side using the Pythagorean theroem

(\sqrt{1} + x)^2 = (\sqrt{1 -x } )^2 + x^2

1 + x^2 = 1 - x^2 + x^2

x = \sqrt{\frac{1 + x^2}{1 -x^2} }

cos A = x/hypotenuse

cos A = \frac{\sqrt{\frac{1+x^2}{1 -x^2} } }{\sqrt{1} +x}

cos A = √(1 + x²)/ (1 - x²) /√1 + x

Thus, the value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

Learn more about trigonometric identities here:

brainly.com/question/7331447

#SPJ1

6 0
1 year ago
In a class of 6, there are 2 students who forgot their lunch.
Mazyrski [523]

Answer:

the answer is 2.78 percent

5 0
1 year ago
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