I agree with you because theta could be acute or obtuse, and if obtuse, negative value.
Answer:
(7, 0).
Step-by-step explanation:
Where the diagonal lines overlap to form squares is where the solutions to the inequality lies.
The point (7, 0) lies in that region.
Answer:
see explanation
Step-by-step explanation:
Since p(x) = x² + 2 , if x ≤ 4
For x = 4 then this is included in the inequality x ≤ 4
whereas x > 4 does not include x = 4 but values greater than 4
Thus to evaluate x = 4 use p(x) = x² + 2
