The structure of Methanol (CH₃OH) is shown below. This structure contains
2 lone pair of electrons on oxygen (highlighted red). Electronic configuration of oxygen is,
Oxygen = 8 = 1s², 2s², 2px², 2py¹, 2pz¹
There are six electrons in valence shell of oxygen, among these six electrons two electrons are unpaired and involved in forming covalent bond with hydrogen and carbon, while remaining 4 electrons in pair (i.e. 2s², 2px²) exists as lone pairs.
<u>Answer:</u> The phase change process in which solids gets converted to gases is sublimation.
<u>Explanation:</u>
For the given options:
<u>Option a:</u> Condensation
It is a type of process in which phase change occurs from gaseous state to liquid state at constant temperature.

<u>Option b:</u> Melting
It is a type of process in which phase change occurs from solid state to liquid state at constant temperature.

<u>Option c:</u> Sublimation
It is a type of process in which phase change occurs from solid state to gaseous state without passing through the liquid state at constant temperature.

<u>Option d:</u> Deposition
It is a type of process in which phase change occurs from gaseous state to solid state without passing through the liquid state at constant temperature.

Hence, the phase change process in which solids gets converted to gases is sublimation.
Answer:
Ch4 Is an ion so the molecule yes 5
Explanation:
Sry for bad Engish me polish
<h3>
Answer:</h3>
1.43 × 10⁻²⁰ mol Li
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
8.63 × 10³ atoms Li
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:

- Multiply/Divide:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
1.43355 × 10⁻²⁰ mol Li ≈ 1.43 × 10⁻²⁰ mol Li