<u>Answer:</u> The freezing point of solution is -0.454°C
<u>Explanation:</u>
Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.
The equation used to calculate depression in freezing point follows:

To calculate the depression in freezing point, we use the equation:

Or,

where,
Freezing point of pure solution = 0°C
i = Vant hoff factor = 2
= molal freezing point elevation constant = 1.86°C/m
= Given mass of solute (KCl) = 5.0 g
= Molar mass of solute (KCl) = 74.55 g/mol
= Mass of solvent (water) = 550.0 g
Putting values in above equation, we get:

Hence, the freezing point of solution is -0.454°C
1.54 x 10^-10 (ten to the negative tenth power)
Answer:
1) correct
2) incorrect
3) correct
4)incorrect
Explanation:
1) A Lewis acid is a substance that accepts a nonbonding pair of electrons.
A Bronsted-Lowry acid is a substance that donates a proton H⁺
Since the donation of a proton involves the acceptance of a pair of electrons, every Bronsted-Lowry acid is also a Lewis acid.
2)A Lewis acid not necessarily needs to have a proton to be donated.
3) Conjugated acids of weak bases are strong acids and conjugated acids of strong bases are weak acids.
4)K⁺ comes from a strong base, therefore is does not have an acidic behaviour.
Answer:
Explanation:
complete combustion reaction of ethane is given by the reaction
2C2H6+7O2..............4CO2+6H2O
no of moles in 34 grams of O2=34/32=1.063
7mole of O2 produced 6 moles of H2O
therefore 1.063 moles of O2 produced=1.063*6/7=0.9 moles
now 0.9 moles of H2O contain how much grams=0.9*18=16.2 grams