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galina1969 [7]
3 years ago
8

Three elements have the electron configurations 1s2 2s2 2p6 3s2 3p6, 1s2 2s2 2p6 3s2, and

Chemistry
1 answer:
lakkis [162]3 years ago
8 0

Explanation:

First element

1s2 2s2 2p6 3s2 3p6

Atomic Number = 18

Element = Argon

Second Element

1s2 2s2 2p6 3s2

Atomic Number = 12

Element = Magnesium

Second Element

1s2 2s2 2p6 3s2 3p6 4s1

Atomic Number = 19

Element = Potassium

In the periodic table;

The general trend is for ionization energy to increase moving from left to right across an element period. It would decrease down the group.

Both Argon and Magnesium are on the same period. Potassium is o the period below.

This leads us to;

Magnesium - 0.7377 MJ/mol

Argon -  1.505 MJ/mol

Potassium - 0.4189 MJ/mol

The atomic radius of atoms generally decreases from left to right across a period.  It would increase down the group.

This leads to;

Magnesium - 1.60

Argon -  0.94

Potassium - 2.35

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Which of the following equations represents an exothermic reaction? (Select all that apply.)
frez [133]

Answer:

CH₄ + 2O₂ ⟶ CO₂ + 2H₂O + 212 800 cal

Step-by-step explanation:

CH₄ + 2O₂ ⟶ CO₂ + 2H₂O + 212 800 cal  

The heat is on the right-hand side of the equation, so the reaction is releasing heat.

The reaction is <em>exothermic</em>.

A is <em>wrong</em>. Your sign of ΔH is wrong, because graphite is the more stable form of carbon. We must add energy to graphite to convert it to diamond, so the process is<em> endothermic</em>.

B and D are <em>wrong</em>, because a ΔH > 0 indicates an <em>endothermic</em> reaction.

7 0
3 years ago
Read 2 more answers
How many molecules of NH3 are produced from 8.01x10-4g of H2
lara31 [8.8K]

Answer:

1.61 x 10²⁰ molecules

Explanation:

Given parameters:

Mass of the hydrogen gas  = 8.01 x 10⁻⁴g

Unknown

Number of molecules of NH₃ = ?

Solution:

Given reaction:

                     N₂  +  3H₂   →   2NH₃

We have to solve from the known to the unknown

  • The known specie is the mass of H₂ ;

             find the number of moles of the specie;

    number of moles = \frac{mass}{molar mass}

     Molar mass of H₂ = 2(1) = 2g/mol

   Number of moles  = \frac{0.0008}{2}   = 0.0004mol

  • 3 moles of H₂   will produce 2 moles of NH₃

      0.0004 moles of H₂ will produce \frac{0.0004 x 2}{3}   = 0.00027moles of NH₃

   1 mole of a substance contains 6.02 x 10²³ molecules

     0.00027mole of NH₃ will contain 0.00027 x 6.02 x 10²³

                               = 1.61 x 10²⁰ molecules

4 0
3 years ago
What happens more when cooking, chemical changes or physical changes?
sineoko [7]
I hope I’m not wrong on this one but I think chemical changes

Reasoning: I took culinary and we talked more on chemistry than culinary

If I’m wrong sorry
5 0
3 years ago
Read 2 more answers
A mixture of 0.307 M Cl 2 , 0.465 M F 2 , and 0.706 M ClF is enclosed in a vessel and heated to 2500 K . Cl 2 ( g ) + F 2 ( g )
monitta

<u>Answer:</u> The equilibrium concentration of chlorine gas, fluorine gas and ClF gas is 0.159 M, 0.317 M and 1.002 M respectively.

<u>Explanation:</u>

We are given:

Initial concentration of chlorine gas = 0.307 M

Initial concentration of fluorine gas = 0.465 M

Initial concentration of ClF gas = 0.706 M

The given chemical equation follows:

                            Cl_2(g)+F_2(g)\rightleftharpoons 2ClF(g)

<u>Initial:</u>                  0.307       0.465       0.706

<u>At eqllm:</u>           0.307-x    0.465-x       0.706+2x

The expression of K_c for above equation follows:

K_c=\frac{[ClF]^2}{[Cl_2][F_2]}

We are given:

K_c=20.0

Putting values in above equation, we get:

20.0=\frac{(0.706+2x)^2}{(0.307-x)(0.465-x)}\\\\x=0.148,0.993

Neglecting the value of x = 0.993 because the equilibrium concentrations of chlorine and fluorine gases will become negative, which is not possible

So, equilibrium concentration of chlorine gas = (0.307 - x) = [0.307 - 0.148] = 0.159 M

Equilibrium concentration of fluorine gas = (0.465 - x) = [0.465 - 0.148] = 0.317 M

Equilibrium concentration of ClF gas = (0.706 + 2x) = [0.706 + 2(0.148)] = 1.002 M

Hence, the equilibrium concentration of chlorine gas, fluorine gas and ClF gas is 0.159 M, 0.317 M and 1.002 M respectively.

5 0
3 years ago
How much energy is required to bring a 30 gram crayon from room temperature, 25 degrees C, to its melting point 49 degrees C?
USPshnik [31]

Answer:

1540.8 Joules of energy is required to bring a 30 gram crayon from room temperature, 25 degrees C, to its melting point 49 degrees C

Explanation:

Crayon is paraffin wax. The specific heat of paraffin wax is 2.14 J/g°C

As we know

Q = m*c *\Delta T

Where

\Delta T is the change in temperature T_2- T_1

m is the mass of the object

c is the specific heat in J/g°C

Substituting the given values, we get -  

Q = 30 * 2.14 *(49-25)\\Q = 1540.8    Joules

1540.8 Joules of energy is required to bring a 30 gram crayon from room temperature, 25 degrees C, to its melting point 49 degrees C

7 0
3 years ago
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