Answer : The balanced chemical equation will be:
(i)
(ii)
Explanation :
Balanced chemical equation : It is defined as the equation in which total number of individual atoms on the reactant side is equal to the total number of individual atoms on product side.
Part (i):
The balanced chemical equation will be:
This reaction is a single displacement reaction in which most reactive element (potassium) displaces the least reactive element (hydrogen) form their solution.
Part (ii):
The balanced chemical equation will be:
This reaction is a single displacement reaction in which most reactive element (zinc) displaces the least reactive element (magnesium) form their solution.
Answer:
The concentration is equal to 1.88x10^-5 M
Explanation:
To calculate the concentration of the unknown solution of 0.699 of absorbance, we must make a graph in Excel and obtain the equation that represents the absorbance vs. molar concentration.
graphing the concentration on the "x" axis and the "y" axis of the absorbance and also linearizing, we have the following expression:
y = 37640x - 0.0089
Clearing x, we have:
x = (y + 0.089)/37640 = (0.699 + 0.089)/37640 = 1.88x10^-5 M
The given question is incomplete. The complete question is as follows.
Nitric acid is a key industrial chemical, largely used to make fertilizers and explosives. The first step in its synthesis is the oxidation of ammonia. In this reaction, gaseous ammonia reacts with dioxygen gas to produce nitrogen monoxide gas and water.
Suppose a chemical engineer studying a new catalyst for the oxidation of ammonia reaction finds that 645. liters per second of dioxygen are consumed when the reaction is run at 195.oC and 0.88 atm. Calculate the rate at which nitrogen monoxide is being produced. Give your answer in kilograms per second. Be sure your answer has the correct number of significant digits.
Explanation:
Chemical equation for the oxidation of ammonia is as follows.
Then volume of per second consumed is as follows.
V =
As this reaction is taking place at a temperature of (468.15 K) and pressure 0.88 atm. Hence, moles of consumption of are calculated as follows.
n =
=
= 14.77 mol /sec
When 5 moles of produces 4 moles of NO then the amount of NO produced from 14.77 mol
= 354.60 g/s
Therefore, NO formed per second is as follows.
= 0.35 kg/s
Thus, we can conclude that the rate at which nitrogen monoxide is being produced is 0.35 kg/s.
Answer: The stratosphere!!