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tankabanditka [31]
3 years ago
13

Do ocean currents affect aquatic life? What do you think and why?

Physics
1 answer:
4vir4ik [10]3 years ago
4 0

Answer: By moving heat from the equator toward the poles, ocean currents play an important role in controlling the climate. Ocean currents are also critically important to sea life.

Explanation: Plzz mark me as brainliest !!

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<span>If you apply 100.0 N of force to lift an object with a single, fixed pulley, then the resistive force is also equivalent to 100 Newtons of force. Since the weight of the object was not mentioned, it is assumed that it has already been taken into account in the 100 N value of force. This follows Newton's law of motion of equal action and reaction.</span>
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10 A particle in circular motion performs 30 oscillations in 6<br> seconds. Its angular velocity is?
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Explanation:

Let omega = angular velocity (in rad/s). Then

omega = (# of oscillations)/(6 s)

= (30 osc)/(6 s) = 5 osc/s

We need to convert this to rad/s:

omega = (5 osc/s)(2π rad/osc)

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if the strength of the magnetic feild at a is 200 units and the strength of the magnetic field at b is 50 units what is the dist
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A compound wall consists of parallel layers of two different materials, 10 cm of brick and 2 cm of wood. If the difference of te
RSB [31]

The temperature difference between the wooden wall is 16⁰C, and the heat current per square metre of the wall is 7,325 W/m².

<h3>Temperature difference between the wooden wall</h3>

The temperature difference between the wooden wall is calculated as follows;

  • Let the brick wall =  wall A
  • Let the wooden wall = wall B
  • Let the area of the walls = A

\frac{dQ_A}{dt } = \frac{dQ_B}{dt} \\\\\frac{K_A \Delta T_A \times  A}{L_A} = \frac{K_B \Delta T _B \times A}{L_B}\\\\\frac{K_A \Delta T_A }{L_A} = \frac{K_B \Delta T _B}{L_B}\\\\\frac{0.5 \times 20}{0.1} = \frac{0.125 \times \Delta T _B }{0.02} \\\\100 = 6.25\Delta T _B\\\\\Delta T _B = \frac{100}{6.25} \\\\\Delta T _B = 16 \ ^oC

<h3 /><h3>Heat flowing in the walls</h3>

Q = KL(ΔT)

Q = 0.5 x 0.1 x (20 + 273)

Q = 14.65 W

<h3>Heat current per square meter of the Walls</h3>

QA = W/A

QA = (14.65)/A

  • Let the area of the wall = 10 cm x 2 cm = 0.1 m x 0.02 m = 0.002 m².

QA = 14.65/0.002

QA = 7,325 W/m²

Learn more about thermal conductivity here: brainly.com/question/11213835

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3 years ago
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