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4 years ago

How does a shiny , silver and smoothsurface reduce the heat loss of a hot object to its cooler surroundings

Physics

1 answer:

crimeas [40]4 years ago

5 0

<h2>Answer:</h2>

<u>Shiny surface are poor radiators of heat </u>

<h2>Explanation:</h2>

A shiny , silver and smooth surface reduce the heat loss of a hot object to its cooler surroundings because good radiators and good absorbed of heat have dull, black and rough surfaces while on the other hand poor radiators have smooth and shiny surfaces therefore they reduce the heat loss of a hot object.

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While taking the stairs it takes you 10 seconds to reach the top. The next time you take the same stairs, it takes you 5 seconds

Ksju [112]

Answer:

P₂ = 2 P₁

we conclude that in the second time the power used is double that in the first rise

Explanation:

In this exercise we are asked the power to climb the stairs, if we assume that we go up with constant speed, we use an energy equal to the potential energy due to the difference in height of the stairs, as this height is constant the potential energy does not change and therefore therefore the energy used by us does not change either.

Now we can analyze the required power,

P = W / t

From the analysis of the previous paragraph the work is equal to the energy used, according to the work energy theorem,

therefore the first time the power is

P₁ = E / 10

P₁ = 0.1 E

for the second time the power is

P₂ = E / 5

P₂ = 0.2 E

we see that the power in the second case is

P₂ = 2 P₁

Therefore, we conclude that in the second time the power used is double that in the first rise.

6 0

3 years ago

If the net force acting on an object is not zero, then the object is definitely

balu736 [363]

Answer:

Explanation:

Since the net force is changing, and not the speed, it is C

Hope this helped!

8 0

3 years ago

A satellite in a nearly circular orbit is 2000 km above earth's surface. the radius of earth is approximately 6400 km. if the sa

Ann [662]

Velocity is computed using the formula:

$v= \frac{d}{t}$
Where:
V = speed
d = distance traveled
t = time/period

First you need to consider that the orbit is circular. To get the measurement or the distance going around Earth, you will need to get the circumference of the path.

$C = 2 \pi r$

Where:
C = circumference
π = 3.14
r = radius

The Earth has a radius of 6,400km, but you also need to consider that the satellite is orbiting above the surface of the Earth, so you add in the 2,000km to that radius.

r = 6,400Km + 2,000Km = 8,400Km

Next step is to insert that into our circumference formula:

$C = 2 \pi r$
$C = 2 \pi 8,400Km$
$C = 52,778.76 Km$

The distance traveled would then be 52,778.76Km

Now that we have the distance, we can then get the velocity:

$v= \frac{d}{t}$
$v= \frac{52,778.76Km}{12hrs}$
$v= 4,398.23km/hr$

The speed of the satellite is 4,398.23km/hr.

7 0

3 years ago

What creates the energy of the Sun?

Svet_ta [14]

Answer:

Explanation:

During nuclear fusion, the high pressure and temperature in the sun's core cause nuclei to separate from their electrons. Hydrogen nuclei fuse to form one helium atom.

5 0

3 years ago

Charge is distributed uniformly along a long straight wire. the electric field 2 cm from the wire is 20 n/c. the electric field

Serjik [45]

The electric field 4cm from the wire is

$É = 10nc { }^{ - 1}$

Given:

charge is distributed uniformly along a long straight wire.

electric field 2cm from the wire is 20n/c

To find:

electric field 4cm from the wire

what is electric field?

Electric field is the region around charge particle or charged body in which if another charge is placed it experiences electrostatic force.An electric field is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.

$E ∝ \frac{1}{r}$