If we're interested in knowing the rate at which light energy is received by a unit of area on a particular surface, we're reall
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PART a)
As we know that gravitational potential energy is given by the formula
here we can see that gravitational potential energy inversely varies with the distance
so here when distance from the sun is minimum then magnitude of gravitational potential energy is maximum while since it is given with negative sign so its overall value is minimum at that position
So gravitational potential energy is minimum at the nearest point and maximum at the farthest point
PART b)
Since we know that sum of kinetic energy and potential energy is constant here
so the points of minimum potential energy is the point where kinetic energy is maximum which means speed is maximum
So here speed is maximum at the nearest point
Part C)
since gravitational potential energy inversely varies with distance so it's graph will be like hyperbolic graph with distance
Answer:
(a) 8.362 rad/sec
(b) 6.815 m/sec
(c) 9.446
(d) 396.22 revolution
Explanation:
We have given that diameter d = 1.63 m
So radius
Angular speed N = 79.9 rev/min
(a) We know that angular speed in radian per sec
(b) We know that linear speed is given by
(c) We have given final angular velocity
And
Time t = 63 sec
Angular acceleration is given by
(d) Change in angle is given by