If we're interested in knowing the rate at which light energy is received by a unit of area on a particular surface, we're reall
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Answer:
6.88 mA
Explanation:
Given:
Resistance, R = 594 Ω
Capacitance = 1.3 μF
emf, V = 6.53 V
Time, t = 1 time constant
Now,
The initial current, I₀ =
or
I₀ =
or
I₀ = 0.0109 A
also,
I =
here,
τ = time constant
e = 2.717
on substituting the respective values, we get
I =
or
I =
or
I = 0.00688 A
or
I = 6.88 mA
Answer:
a = 0.45 m/s²
Explanation:
The given question is ''Calculate the acceleration that produces a force of 40 N on a body with 88 kg of mass".
Given that,
Force, F = 40 N
Mass of the body, m = 88 kg
The net force acting on the body is given by :
F = ma
Where
a is the acceleration of the body
So, the required acceleration is 0.45 m/s².