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Kipish [7]
3 years ago
14

Pls help me with this

Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
6 0
U is correct on the first one
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If 105 J of energy is used in 103 s, what is the average power consumption in watts?
jekas [21]
Power = work/time

P = 105J/103s

P = <span>1.019 watts</span>
4 0
3 years ago
(b) A lift (elevator) in a high building transports 12 passengers, each of mass 65 kg, through a
PSYCHO15rus [73]

Explanation:

P =F * v

F = m * a = 65 kg * 9.81 ms^-2 * 12 passengers

v = d/t = 150m / 64 s

I think you can calculate and substitute this units should be watts

5 0
3 years ago
Why does The human population continue to grow exponentially
svlad2 [7]
Global human population growth is around 75 million annually, or 1.1% per year. The global population has grown from 1 billion in 1800 to 7 billion in 2012. Globally, the growth rate of the human population has been declining since 1962 and 1963, when it was 2.20% per annum. In 2009, the estimated annual growth rate was 1.1%. The CIA World Factbook gives the world annual birthrate, mortality rate, and growth rate as 1.89%, 0.79%, and 1.096% respectively. The last 100 years have seen a rapid increase in population due to medical advances and massive increase in agricultural productivity.
6 0
3 years ago
Read 2 more answers
A 350-km-long high-voltage transmission line 2.00 cm in diameter carries a steady current of 1,010 A. If the conductor is copper
Masja [62]

Answer:

t = 47 years

Explanation:

To find the number of years in which the electrons cross the complete transmission, you first calculate the drift velocity of the electrons in the transmission line, by using the following formula:

v_d=\frac{I}{nAq}         (1)

I: current = 1,010A

A: cross sectional area of the transmission line = π(d/2)^2

d: diameter of the transmission line = 2.00cm = 0.02 m

n: free charge density = 8.50*10^28 electrons/m^3

q: electron's charge = 1.6*10^-19 C

You replace the values of all parameters in the equation (1):

v_d=\frac{1010A}{(8.50*10^{28}m^{-3})(\pi(0.02m/2)^2)(1.6*10^{-19}C)}\\\\v_d=2.36*10^{-4}\frac{m}{s}

with this value of the drift velocity you can calculate the time that electrons take in crossing the complete transmission line:

t=\frac{d}{v_d}=\frac{350km}{2.36*10^{-4}m/s}=\frac{350000m}{2.36*10^{-4}m/s}\\\\t=1,483,050,847\ s

Finally, you convert this value of the time to years:

t=1,483,050,847s*\frac{1\ year}{3.154*10^7s}=47\ years

hence, the electrons take around 47 years to cross the complete transmission line.

7 0
3 years ago
A city uses a water tower to store water for times of high demand. When demand is light, water is pumped into the tower. When de
love history [14]

Answer:

The height of the tower will be 35.714 m

Explanation:

We have given gauge pressure P=350kPa=350\times 10^3Pa

Density of water \rho =1000kg/m^3

We have to find the height of the tower h

We know that gauge pressure is given by P=\rho gh

350\times 10^3=100 0\times 9.8\times h

h=35.714m

So the height of the tower will be 35.714 m

6 0
3 years ago
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