Answer:
1/1024 is the proportion of the F2 genotypes will be recessive for all five loci
Explanation:
When crossing between both parents, all genotypes will give us 100% AaBcCcDdEe. When a self-fertilization is performed this means that it can have a cross for example of two flowers of the same plant with the genotype AaBcCcDdEe In this way, given the law of independent segregation which states that the alleles of two or more different genes are distributed in the gametes independently of each other. The proportion that at this junction the alleles are aa (1/4) bb (1/4) cc (1/4) dd (1/4) and ee (1/4). The proportions (1/4)* (1/4)*(1/4)*(1/4)*(1/4) are multiplied, obtaining a value of 1/1024
If a plant cell had a mutation such that the cyclic electron flow is observed at a much higher rate, which photosystem is most likely mutated such that energy is absorbed at a lower rate?
PSI
PSII
Answer:
PSII
Explanation:
Non-cyclic phosphorylation involves both PSI and PSII. The process starts with the splitting of water and excitation of electrons of the reaction center of PSII upon the absorption of solar energy at the wavelength of 680 nm. Any mutation in PSII would not allow the non-cyclic phosphorylation to occur when only cyclic phosphorylation would occur. The process of cyclic phosphorylation includes only PS I. Its reaction center absorbs maximum light at 700 nm and is cycled back while supporting ATP synthesis. Therefore, if a plant performs cyclic phosphorylation at a higher rate and absorbs less energy, this means that mutation was in PSII.
Explanation:
Cell wall is not present in animal cells .
Answer:
WAVE #3
Explanation:
Radio waves have the longest wavelengths in the EM spectrum, according to NASA, ranging from about 0.04 inches (1 millimeter) to more than 62 miles (100 kilometers). They also have the lowest frequencies, from about 3,000 cycles per second, or 3 kilohertz, up to about 300 billion hertz, or 300 gigahertz
