Hi there,
Let's get started,
The line is parallel to the line whose equation is y = 4x + 1.
So the slope will be the same.
The equation that would be possible is :
y = 4x + c
By the way, we know that the line passes through (-3 ; 2).
We just have to substitute these values in the equation in order to find the value of c.
(x ; y) ==> x = -3 and y = 2
Let's do this then,
2 = 4(-3) + c
c = 2 - 4(-3)
c = 2 + 12
c = 14
In short, the answer would be :
y = 4x + 14.
Hope this helps !
Photon
Answer:
no
Step-by-step explanation:
its is not a solution, however if the equal sign actually looks like
![\leqslant](https://tex.z-dn.net/?f=%20%5Cleqslant%20)
then it would be yes
1 (1+4) (4+6) (6+4) (4+1) 1
1 5 10 10 5 1
Algebraically, linear functions are polynomials with highest exponent equal to 1 or of the form y = c where c is constant. Nonlinear functions are all other functions. An example of a nonlinear function is y = x^2. This is nonlinear because, although it is a polynomial, its highest exponent is 2, not 1.