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4 years ago

PLEASE HELP 13 POINTS

Mathematics

1 answer:

aalyn [17]4 years ago

3 0

Circumference of circle = π × Diameter

= π × 18 cm

= 56.54867 or 56.54 to 1 dp

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Jillian is at her favorite clothing store and has found a pair of pants that are on sale for 20% off the regular price. They are

Damm [24]

Answer: $5,60 will be taken off the price

Step-by-step explanation:

Take off = regular price·20/100

Take off = $28·20/100 = $560/100 = $5,60

Price after discount = $28 - $5.60 = $22.4

Answer: $5,60 will be taken off the price

<h2>Spymore</h2>

3 0

4 years ago

Please help Question is on the Picture

zepelin [54]

The slope of machine 1 is 0.3. And machine 2 is 3/8. Hope this helped

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3 years ago

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Item 15The entrance of a tunnel can be modeled by y=−11/50(x−4)(x−24), where x and y are measured in feet. The x-axis represents

Evgen [1.6K]

Answer:

The with of the tunnel at the ground level is 20 feet

Step-by-step explanation:

The equation that model the entrance of the tunnel is y = -11/50(x - 4)(x - 24)

Where the dimensions of 'x' and 'y' are in feet and the x-axis represent the ground level

The y-axis represent the height, and the equation is a quadratic equation with the shape of an upside down parabola to represent the shape of the entrance to the tunnel

The two coordinates of the parabola at the ground level (where y = 0)

of the tunnel entrance from which we can find the width by subtraction are given when y = 0 as follows;

y = 0 = -11/50(x - 4)·(x - 24)

∴ (x - 4)·(x - 24) = 0/(-11/50) = 0

When (x - 4)·(x - 24) = 0, x = 4, or x = 24

The coordinates at the ground corners of the tunnel entrance are therefore;

(4, 0), and (24, 0)

The with of the tunnel at the ground level is equal to the width of the parabola at the x-axis, which is given as follows;

The width of the parabola at the x-axis = Distance between points (4, 0), and (24, 0)

∴ The width of the parabola at the x-axis = √((0 - 0)² + (24 - 4)²) = √(24 - 4)² = 24 - 4 = 20 (distance between points having the same y-coordinates)

The width of the parabola at the x-axis = 20 ft. = The with of the tunnel at the ground level

∴ The with of the tunnel at the ground level = 20 feet.

8 0

3 years ago

I need help with trigonometry Again..

tigry1 [53]

Answer: C. - √2

Step-by-step explanation:

Given requirements from the question

Find the exact value of sec 135°

Convert into common trigonometric expression

sec = secant

secx = 1 / cosx

Therefore, sec 135° = 1 / (cos 135°)

Find the reference angle

135° is quite a complicated angle, but it is possible to simplify it by finding its reference angle.

Since 135° is in the second quadrant, its reference angle will be

180° - 135° = 45°

However, we need to consider the positive and negative.

In a coordinate plane, the clue is (A S T C), which corresponds to the positive values in each quadrant. In the QI, "All" are positive. In the QII, sine is positive. In the QIII, the tangent is positive. In QIV, cosine is positive.

Therefore, when the value of cosine is in QII, it is negative.

The reference angle = - (1 / cos 45°)

Determine the final value

Given that the reference angle = - (1 / cos 45°)

cos 45° = 1 / √2

Therefore:

sec 135° = - (1 / cos 45°) = - (1 / (1 / √2)) = $\boxed{-\sqrt{2} }$

Hope this helps!! :)

Please let me know if you have any questions

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2 years ago

Find the surface area

nlexa [21]

Answer:15

Step-by-step explanation:

i solved it!

7 0

3 years ago

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