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Digiron [165]
3 years ago
10

Find area of a rectangle with vertices -9,3 -9,-7 -6,-7 and -6,-3

Mathematics
1 answer:
VikaD [51]3 years ago
3 0
4 times 3 equals 12.
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F(x)=3x-4 and g(x) = x2 find the value of f(3)-g(2) <br><br> show all work
zheka24 [161]

Answer: 1

f(x) = 3x - 4 => f(3) = 3.3 - 4 = 9 - 4 = 5

g(x) = x² => g(2) = 2² = 4

=> f(3) - g(2) = 5 - 4 = 1

Step-by-step explanation:

3 0
3 years ago
What’s equivalent (2x^5)^3
Over [174]

Answer:

8x^15

Step-by-step explanation:

(2x5)3

=(2x5)3

=2x5*2x5*2x5

=8x15

6 0
3 years ago
FIND THE MEASURE OF EACH MISSING ANGLE HURRY DUE AT 10
max2010maxim [7]
Because of a linear pair then because of vertical angles and because all angles have to be 180 added up

5 0
3 years ago
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
Sarah had 7.1 pints of blue and white paint, she uses 3/4 of blue paint. How many pints is left. How do I do this problem
Alexxx [7]

Answer:5.325 or 213 / 40

anymore questions ask me ;)

7 0
3 years ago
Read 2 more answers
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