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Digiron [165]
3 years ago
10

Find area of a rectangle with vertices -9,3 -9,-7 -6,-7 and -6,-3

Mathematics
1 answer:
VikaD [51]3 years ago
3 0
4 times 3 equals 12.
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Solve the inequality.
Vika [28.1K]

Answer:

Option C is correct

Step-by-step explanation:

      5c – 20 ≤ 15c + 10

<=> 5c - 15c ≤ 20 + 10

<=>-10c ≤ 30

<=> c ≥ -3

Hope this helps!

6 0
3 years ago
Read 2 more answers
Explain the Error
Dvinal [7]
1+1+1+1=4
2+2+2+2=16
3+3+3+3=?

I won against: Marilyn Wright-Brown
8 0
3 years ago
What is the first term of the geometric sequence presented in the table below?
Leto [7]
Fron the table given:

A3 = 112,
A8 = - 3,584

An = A1 *r ^ (n-1)

=> A3 = A1 (r^2) = 112

A8 = A1(r^7) = - 3,584

=> - 3584 / 112 = (r^7) / (r^2)

=> (r^5) = - 32

=> r = - 2

=> A1 (- 2)^2 = 112

=> A1 = 112 / 4 = 28

Answer: a1 = 28
8 0
3 years ago
Can I pls get some help
Natali5045456 [20]

1,905.63 is the correct answer

5 0
2 years ago
(HELP ME 15 PTS)
kap26 [50]

Answer:   \bold{\dfrac{27x^2y^3}{16}}

<u>Step-by-step explanation:</u>

\dfrac{(3x^2y^5)^3}{(2xy^3)^4}\\\\\\=\dfrac{3^3\cdot x^{2\cdot 3}\cdot y^{5\cdot 3}}{2^4\cdot x^4\cdot y^{3\cdot 4}}\\\\\\=\dfrac{27\cdot x^6\cdot y^{15}}{16\cdot x^4\cdot y^{12}}\\\\\\=\dfrac{27\cdot x^{6-4}\cdot y^{15-12}}{16}\\\\\\=\dfrac{27\cdot x^2\cdot y^3}{16}

8 0
2 years ago
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