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salantis [7]
3 years ago
6

Which phrases can be used to represent the inequality 12-3x≥9? Check all that apply. (multi choice)

Mathematics
1 answer:
balandron [24]3 years ago
8 0

Answer:

Which phrases can be used to represent the inequality 12-3x≥9? Check all that apply. (multi choice)

<u> A Twelve less than three times a number is greater than or equal to nine. </u>

B Twelve less than three times a number is at least nine.

C Twelve less three times a number is at least nine.

D Twelve minus the product of three and a number is no more than nine.

E Twelve less three times a number is at most nine.

F Twelve minus the product of three and a number is no smaller than nine.

G Twelve minus the product of three and a number is larger than nine.

Step-by-step explanation:

12 - 3x>=9

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a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-
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Answer:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

M = \frac{1}{2}(Lower + Upper)

Where

Lower \to Lower class interval

Upper \to Upper class interval

So, we have:

Class 63-65:

M = \frac{1}{2}(63 + 65) = 64

Class 66 - 68:

M = \frac{1}{2}(66 + 68) = 67

When the computation is completed, the frequency distribution will be:

\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1}  & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7}  & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

\bar x = 70.2903

\sigma = 3.5795

<em>See attachment for result of 1-VarStats</em>

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Step-by-step explanation:

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Read 2 more answers
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