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Andrei [34K]
3 years ago
8

The area of the parallelogram is 96 square miles. Find its base and height.

Mathematics
1 answer:
MakcuM [25]3 years ago
8 0

You can't. There are an infinite number of different parallelograms,
with different dimensions, that all have area of 96 square miles.

Knowing the area doesn't tell you the dimensions.

Here are a few parallelograms with areas of 96 square miles:

-- square, every side  4√6  miles long

-- rectangle, 12 miles long, 8 miles wide

-- parallelogram, base=32 miles,    height=3 miles

There are an infinite number of others.


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Need help with this.
Ber [7]
Slope is -1
Y intercept 3
X Intercept 4
Sorry I do t know the others
Haven’t gone over that

Hope this helps
6 0
3 years ago
Read 2 more answers
i need help on this problem i know how to do this types of problem but i dont get this problem i need hep thank you
Sever21 [200]

Answer:

B: 72

Step-by-step explanation:

Split the shape into separate rectangles! It will make the problem much easier. You can split it so that you will have a 12 x 3 rectangle and a 6 x 6 rectangle because you subtract 3 from 9 and subtract 6 from 12.

12 x 3 = 36

6 x 6 = 36

36 + 36 = 72

Let me know if you're still confused!

8 0
3 years ago
Read 2 more answers
Please help me on this math please
makkiz [27]
1=60
2=120
3=120
4=180
5=240
6=300
and you have arrived bu now. :)
Good luck with your lessons, hope I helped. :D
8 0
3 years ago
Using the following figure, match the angles in the first column with their corresponding congruent angles in the second column.
Rus_ich [418]

Answer:

∠6 = ∠8

∠2 = ∠6

Step-by-step explanation:

Lines 'p' and 'q' are the parallel lines and line 'l' is a transversal line intersecting these lines at two distinct points.

By the property of alternate interior angles,

∠3 = ∠5

By the property of vertically opposite angles,

∠6 = ∠8

By the property of corresponding angles,

∠2 = ∠6

3 0
3 years ago
The graph of f ′ (x), the derivative of f of x, is continuous for all x and consists of five line segments as shown below. Given
Rom4ik [11]

f'(x)\ge0 for all x in [-3, 0], so f(x) is non-decreasing over this interval, and in particular we know right away that its minimum value must occur at x=-3.

From the plot, it's clear that on [-3, 0] we have f'(x)=-x. So

f(x)=\displaystyle\int(-x)\,\mathrm dx=-\dfrac{x^2}2+C

for some constant C. Given that f(0)=7, we find that

7=-\dfrac{0^2}2+C\implies C=7

so that on [-3, 0] we have

f(x)=-\dfrac{x^2}2+7

and

f(-3)=\dfrac52=2.5

5 0
3 years ago
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