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2 years ago

7

In a lab experiment, 50 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to doub

le every 20 hours. How many bacteria would there be after 8 hours, to the nearest whole number?

2 answers:

timurjin [86]2 years ago

8 0

Divide 50 and 20 and you get 2.5 then multiply that with 8 and you’ll get 20
THE ANSWER IS 20

kolbaska11 [484]2 years ago

4 0

Answer:

y=65.975395539

y≈66

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The molar mass of AlCl3 is 133.34 g/mol. How many molecules of AlCl3 are there in 2 g?

Mnenie [13.5K]

To solve this problem, we have to apply mole-concept to this and we would need the molar mass of AlCl3. 2g of AlCl3 contains 9.034*10^21 molecules.

<h3>Number of Molecules in 2g of AlCl3</h3>

The molar mass of AlCl3 is given as 133.34g/mol

Data;

mass = 2g
molar mass = 133.34g/mol

Using the mole concept, we can equate the molar mass to the number of molecules present in the entity.

$133.34g = 6.023*10^2^3$

If we equate this

$133.34g = 6.023*10^2^3\\2g = x molecules\\x = \frac{2*6.023*10^2^3}{133.34} \\x = 9.034*10^2^1 molecules$

From the calculations above, 2g of AlCl3 contains 9.034*10^21 molecules.

Learn more on mole concept here;

brainly.com/question/21150359

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1 year ago

At a summer camp, there are 40 boys out of 70 campers. What is this ratio written as a fraction in simplest form?

madam [21]

Answer:

40:70 becomes 20:35 which becomes 4: 7.

The answer is 4:7

Step-by-step explanation:

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2 years ago

tommy's toy car sits 5 feet from the gound. it goes down the ramp at .25 feet per second. how far does it go in 1.5 seconds?

Tamiku [17]

Answer:

0.375 feet.

Step-by-step explanation:

Multiply .25 by 1.5 to get 0.375.

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2 years ago

Due to a membership drive for a public television station, the current membership is 125% of what it was a year ago. The current

Oliga [24]

$x(1.25)=1200$

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2 years ago

Read 2 more answers

I need the answer for this problem please

Savatey [412]

Answer:

B

Step-by-step explanation:

Find all probabilities:

A. False

$Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}$

B. True

$Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}$

C. False

$Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}$

D. False

$Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}$

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3 years ago