System A:
6x + y = 2
-x - y = -3
System B:
2x - 3y = -10
-x-y = -3
Solve:
System A:
6x + y = 2
y = 2 - 6x
-x - (2-6x) = -3
-x - 2 + 6x = -3
5x = -3 + 2
5x = -1
x = -1/5
y = 2 - 6(-1/5)
y = 2 + 6/5
y = 2 + 1.2
y = 3.2 System A: x = -1/5 or -0.2 ; y = 3 1/5 or 3.2
System B:
2x - 3y = -10
2x = -10 + 3y
x = -5 + 1.5y
-x - y = -3
-(-5 + 1.5y) -y = -3
5 - 1.5y - y = -3
-2.5y = -3 - 5
-2.5y = -8
y = 3.2
x = -5 + 1.5(3.2)
x = -5 + 4.8
x = -0.2 System B: x = -0.2 ; y = 3.2
<span>B) They will have the same solution because the first equations of both the systems have the same graph.</span>
what do you need help with?
Y=12/5 + 2x/5
Explanation:
1 & 4 & 6 are the answers
A table will generally give you an output value for each of several input values. To find the average rate of change over some range of inputs, divide the difference between output values by the difference between input values for the corresponding inputs.
For example, consider the table
input .... output
.. 1 ............ 3
.. 3 ........... -5
The average rate of change between these input values is
... (change in output)/(change in input) = (-5 -3)/(3 - 1) = -8/2 = -4.
