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konstantin123 [22]
3 years ago
9

Expand the single bracket 9(7 – b)

Mathematics
2 answers:
wolverine [178]3 years ago
8 0

Answer:

63-9b

Step-by-step explanation:

9(7-b)

=9×7-9×b

=63-9b

nlexa [21]3 years ago
5 0

Answer:

63-9b

Step-by-step explanation:

9 x 7= 63

9 x b= 9b

63-9b

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If the volume of a sphere is 256π/3 what is the radius?
Rzqust [24]

Answer:

4

Step-by-step explanation:

The volume of a sphere is equal to 4/3πr³.

Set up the equation;

4/3πr³=256π/3

Multiple both sides by 3/(4π):

r³=64

r=∛64=4 (ans)

6 0
2 years ago
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(b) In the figure below, m 2AEB= 55° and m AB = 60°. Find m CD.<br><br> m CD =
RUDIKE [14]

Answer:

47 degrees

Explanation:

your welcome

4 0
2 years ago
A clock cog rotates 150 degrees in 20 minutes. How far will far will the same cog rotate in 70 minutes
Alex

Answer:

525 degrees

Step-by-step explanation:

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2 years ago
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Suppose a normal distribution has a mean of 62 and a standard deviation of4. What is the probability that a data value is betwee
saw5 [17]

SOLUTION

From the given data the mean is 62 and standard deviation is 4

It is required to find the probability that a data value is between 57 and 62

That is:

P(57\lt x\lt65)

The z scores is calculated using:

z=\frac{x-\mu}{\sigma}

Using the x values it follows:

z=\frac{57-62}{4}=-1.25

Also,

z=\frac{65-62}{4}=0.75

Thus the required probability is:

P(-1.25The proability is:[tex]P(-1.25This can be expressed as percentage as:[tex]P(-1.25\lt z\lt0.75)=66.8\%

Therefore the correct option is C

8 0
1 year ago
At the start of the year, 15 chameleons were introduced into a zoo. The population of chameleons is expected to grow at a rate o
bearhunter [10]

Answer:

option-B

Step-by-step explanation:

We are given

At the start of the year, 15 chameleons were introduced into a zoo

so, P_0=15

The population of chameleons is expected to grow at a rate of 41.42% every year

so, r=0.4142

and x represents the number of years since the chameleons were introduced into the zoo

now, we can set equation to find total population

and we get

P(x)=P_0(1+r)^x

now, we can plug values

P(x)=15(1+0.4142)^x

P(x)=15(1.4142)^x

Average rate of change between 2 years and 4 years:

we can use formula

A_1=\frac{P(4)-P(2)}{4-2}

now, we can plug values

A_1=\frac{15(1.4142)^{4}-15(1.4142)^{2}}{4-2}

A_1=14.99914

Average rate of change between 4 years and 6 years:

we can use formula

A_2=\frac{P(6)-P(4)}{6-4}

now, we can plug values

A_2=\frac{15(1.4142)^{6}-15(1.4142)^{4}}{6-4}

A_2=29.99770

Average rate of change between 6 years and 8 years:

we can use formula

A_3=\frac{P(8)-P(6)}{8-6}

now, we can plug values

A_3=\frac{15(1.4142)^{8}-15(1.4142)^{6}}{8-6}

A_3=59.99425

now, we will check each options

option-A:

we can see that

A_3-A_2=30

A_3-A_2=30

So, this is FALSE

option-B:

A_1=\frac{1}{2}A_2

So, this is TRUE

option-C:

This is FALSE

option-D:

we got

A_1=\frac{1}{2}A_2

so, this is FALSE


5 0
3 years ago
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