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2 years ago

Find the rate of a/b and complete the equivalent ratio 69

Mathematics

1 answer:

ivann1987 [24]2 years ago

8 0

I am not sure

Step-by-step explanation:

D John <em>Adams</em>

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Which polynomial represents a sum of cubes

Umnica [9.8K]

8x^3+1 is the answer because we can rewrite it as this : (2x)^3 + 1^3

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3 years ago

Who would you solve 8x+-2y-10

olchik [2.2K]

Okay, for this one I would use elimination:

8x+(-2y)-10
or
8x-2y=10
2x=4y
x=2y
8(2y)-2y=10
16y-2y=10
14y=10
y=5/7
x=10/7 or 1 3/7. Hope it help!

8 0

3 years ago

Help me please if you can

tekilochka [14]

Answer:

<D=<J

Step-by-step explanation:

The first answer is the only correct statement. In geometry, congruent angles are shown through the number of arcs on the vertex of an angle. For example, if two different angles both had three arcs on the vertex, then those two angles are congruent. In this figure, both <D and <J have 4 arcs, which means they are congruent. Additionally, both angles are opposite of a line that measures 25 inches. If two angles are opposite of congruent lines, then the angles are also congruent.

3 0

3 years ago

What is a translation (math)

Vikentia [17]

Answer:

Translation is a term used in geometry to describe a function that moves an object a certain distance. The object is not altered in any other way. It is not rotated, reflected or re-sized. In a translation, every point of the object must be moved in the same direction and for the same distance.

Step-by-step explanation:

Hope that helped :)

5 0

3 years ago

Read 2 more answers

An instructor gives her class the choice to do 7 questions out of the 10 on an exam.

Maksim231197 [3]

Answer:

(a) 120 choices

(b) 110 choices

Step-by-step explanation:

The number of ways in which we can select k element from a group n elements is given by:

$nCk=\frac{n!}{k!(n-k)!}$

So, the number of ways in which a student can select the 7 questions from the 10 questions is calculated as:

$10C7=\frac{10!}{7!(10-7)!}=120$

Then each student have 120 possible choices.

On the other hand, if a student must answer at least 3 of the first 5 questions, we have the following cases:

1. A student select 3 questions from the first 5 questions and 4 questions from the last 5 questions. It means that the number of choices is given by:

$(5C3)(5C4)=\frac{5!}{3!(5-3)!}*\frac{5!}{4!(5-4)!}=50$

2. A student select 4 questions from the first 5 questions and 3 questions from the last 5 questions. It means that the number of choices is given by:

$(5C4)(5C3)=\frac{5!}{4!(5-4)!}*\frac{5!}{3!(5-3)!}=50$

3. A student select 5 questions from the first 5 questions and 2 questions from the last 5 questions. It means that the number of choices is given by:

$(5C5)(5C2)=\frac{5!}{5!(5-5)!}*\frac{5!}{2!(5-2)!}=10$

So, if a student must answer at least 3 of the first 5 questions, he/she have 110 choices. It is calculated as:

50 + 50 + 10 = 110

6 0

3 years ago

Find the rate of a/b and complete the equivalent ratio 69​

Find the rate of a/b and complete the equivalent ratio 69