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Sergio [31]
3 years ago
10

Can someone help me with a and b thank you

Mathematics
1 answer:
sdas [7]3 years ago
3 0

Given:

a) Area = 121 ft²

b) Area = 81 yd²

To find:

The side length of each square

Solution:

a) Area = 121 ft²

Area of the square = s²

⇒ s² = 121

Taking square root on both sides.

\Rightarrow \sqrt{s^2} = \sqrt{ 121}

\Rightarrow \sqrt{s^2} = \sqrt{ 11^2}

Square root and squares get canceled.

⇒ s = 11

The length of each side of the square is 11 ft.

b) Area = 81 yd²

Area of the square = s²

⇒ s² = 81

Taking square root on both sides.

\Rightarrow \sqrt{s^2} = \sqrt{ 81}

\Rightarrow \sqrt{s^2} = \sqrt{ 9^2}

Square root and squares get canceled.

⇒ s = 9

The length of each side of the square is 9 yd.

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For each container of tea, McKenzie uses 16 tea bags and 3 cups of sugar. If McKenzie uses 64 tea bags, how many cups of sugar w
cestrela7 [59]
So tis is a ratio  16 is to 3 or 16:3
if use 64 tea bags then how many cups of sugar so
turn 16:3 into fraction
16:3=16/3 or 3/16, it doesn't matter
then you want to find 64:x or 64/x or x/64

we know that 16/3=64/x because it tis an equivalent ratio
so 16/3=64/x
multiply both sdies by (3 times x)
16 times x times 3/3=64 times 3 times x/x
16 times x=64 times 3
16x=192
divide both sdies by 16
x=12
theanswer is 12 cups of sugar
5 0
3 years ago
Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5
givi [52]
<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

and          B= \left[\begin{array}{c}11\\5\end{array}\right]

∴AX=B

adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]

A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

∴A^{-1} =\frac{adj A}{|A|}

So,A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}

A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

X =A^{-1}\times B

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0
3 years ago
PLEASE HEEEEEEEEEEELPPP!!!
miv72 [106K]

Answer:

Im pretty sure the answer is B) f=2.5b

5 0
3 years ago
Read 2 more answers
Solve.
horrorfan [7]
.hello : 
<span>2d−e=7....(1)
d+e=5.....(2)
(1)+(2) : 3d=12
d=4
subsct in (2) : 
4+e=5
e=1
conclusion : 
</span><span>The solution is (4, 1).</span><span>

</span>
4 0
3 years ago
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Who wants a free brainliest
andre [41]
ME PLS I WOULD REALLY POSITIVELY LOVE THAT.
7 0
3 years ago
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