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Sergio [31]
3 years ago
10

Can someone help me with a and b thank you

Mathematics
1 answer:
sdas [7]3 years ago
3 0

Given:

a) Area = 121 ft²

b) Area = 81 yd²

To find:

The side length of each square

Solution:

a) Area = 121 ft²

Area of the square = s²

⇒ s² = 121

Taking square root on both sides.

\Rightarrow \sqrt{s^2} = \sqrt{ 121}

\Rightarrow \sqrt{s^2} = \sqrt{ 11^2}

Square root and squares get canceled.

⇒ s = 11

The length of each side of the square is 11 ft.

b) Area = 81 yd²

Area of the square = s²

⇒ s² = 81

Taking square root on both sides.

\Rightarrow \sqrt{s^2} = \sqrt{ 81}

\Rightarrow \sqrt{s^2} = \sqrt{ 9^2}

Square root and squares get canceled.

⇒ s = 9

The length of each side of the square is 9 yd.

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You get GPS units from two manufacturers, A and B. You get 43% of your units from A and 57% of your units from B. In the past, 2
defon

Answer:

0.5015 = 50.15% probability that it came from manufacturer A.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Defective

Event B: From manufacturer A.

Probability a unit is defective:

2% of 43%(from manufacturer A)

1.5% of 57%(from manufacturer B). So

P(A) = 0.02*0.43 + 0.015*0.57 = 0.01715

Probability a unit is defective and from manufacturer A:

2% of 43%. So

P(A \cap B) = 0.02*0.43 = 0.0086

What is the probability that it came from manufacturer A?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0086}{0.01715} = 0.5015

0.5015 = 50.15% probability that it came from manufacturer A.

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Step-by-step explanation:

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What is the probability that both of Eduardo's partners for the group project will be girls? StartFraction 9 Over 65 EndFraction
tester [92]

Answer:

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Step-by-step explanation:

Total number of students = 26

Number of boys = 10

Number of girls = 26-10

=16

Eduardo has to pull two names out of the hat without replacing them.

First name

Probability= Favourable outcome/Total outcome

Probability of girls=16

Total probability=26

Eduardo has to pull two names out of the hat without replacing them.

Probability= Favourable outcome/Total outcome

=16/26

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For the second name:

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Probability of girls=16-1=15

Total probability=26-1=25

Probability= Favourable outcome/Total outcome

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Probability of both of Eduardo's partner for the group project will be girls=8/13*3/5

=24/65

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