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sveticcg [70]
3 years ago
7

How many Br- ions are there in 2.51 grams of AlBr3

Chemistry
1 answer:
mafiozo [28]3 years ago
7 0

Answer is: there are 1.7·10²² Br⁻ ions.

m(AlBr₃) = 2.51 g; mass of aluminium bromide.

n(AlBr₃) = m(AlBr₃) ÷ M(AlBr₃).

n(AlBr₃) = 2.51 g ÷ 266.7 g g/mol.

n(AlBr₃) = 0.0094 mol; amount of substance.

In one mol of aluminium bromide there are three moles of bromine anions:

n(Br⁻) = 3 · 0.0094 mol.

n(Br⁻) = 0.028 mol.

N(Br⁻) = n(Br⁻) · Na(Avogadro constant).

N(Br⁻) = 0.028 mol · 6.022·10²³ 1/mol.

N(Br⁻) = 1.7·10²².

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Question 2
andrezito [222]

Answer:

A.  Peroxide breaking down into water and oxygen

Explanation:

Generally when it comes to changes, there are physical and chemical changes. In physical changes, there are no new substances been formed, however in chemical change new substances are formed.

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This is a physical change

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3 0
3 years ago
How much heat is released when 24.8 g of ch4 is burned in excess oxygen gas?
balu736 [363]

The given question is incomplete. The complete question is:

How much heat is produced when 24.8 g of CH_4 is burned in excess oxygen gas

Given: CH _4
+2O_2\rightarrow CO_2+2H_2O  ΔH= −802 kJ.

Answer: 1243.1 kJ

Explanation:

Heat of combustion is the amount of heat released on complete combustion of 1 mole of substance.

Given :

Amount of heat released on combustion of  1 mole of methane = 802 kJ kJ/mol

According to avogadro's law, 1 mole of every substance occupies 22.4 L at NTP, weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

1 mole of CH_4 weighs = 16 g  

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16 g of CH_4 on combustion releases heat = 802 kJ

Thus 24.8 g of CH_4 on combustion releases =\frac{802}{16}\times 24.8=1243.1kJ

Thus heat released when 24.8 g of methane is burned in excess oxygen gas is 1243.1 kJ

4 0
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