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3 years ago

At 1.4 atm of pressure a gas has a volume of 111 ML at what pressure will the gas have a volume of 85 ML.

Chemistry

1 answer:

Alona [7]3 years ago

8 0

Answer:

The pressure will be 1, 83 atm

Explanation:

We use Boyle Mariotte's formula: for a given mass of gas at constant temperature, the pressure and volume vary inversely proportionally. We convert the unit ml into L: 111/1000= 0,111 L and 85/1000= 0,085 L.

P1xV1=P2xV2

P2= (P1xV1)/V2=(1,4 atm x 0,111L)/0,085L=<em>1,83 atm</em>

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alina1380 [7]

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2 years ago

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If a molecule diffusing through extracellular fluid travels 1 mm in 1 sec, how long will it take that molecule to diffuse 1 cm?

stealth61 [152]

To determine the time, we can simply do dimensional analysis from the given values. We are given the distance the fluid travels per sec and we are given the required distance to travel. Therefore, we simply divide the required distance with the rate given. It is important to take note with the units.

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3 years ago

5.00 g of a certain Compound X, known to be made of carbon, hydrogen and perhaps oxygen, and to have a molecular molar mass of 7

slega [8]

Answer:

The molecular formula = C6H6

Explanation:

Step 1: Data given

Mass of compound X = 5.00 grams

Mass of products =

CO2 = 16.39 grams

H2O = 3.46 grams

Molar mass CO2 = 44.01 g/mol

Molar mass H2O = 18.02 g/mol

Molar mass C = 12.01 g/mol

Molar mass H = 1.01 g/mol

Molar mass O = 16. 0g/mol

Step 2: Calculate moles

Moles = mass / molar mass

Moles CO2 = 16.93 grams / 44.01 g/mol

Moles CO2 = 0.385 moles

Moles C = 1* 0.385 = 0.385 moles

Moles H2O = 3.46 grams / 18.02

Moles H2O = 0.192 moles

Moles H = 2* 0.192 = 0.384 moles

Step 3: Calculate mass

Mass = moles * molar mass

Mass C = 0.385 moles *12.0 g/mol

Mass C = 4.62 grams

Mass H = 0.39 grams

Mass O = 5.00 - 4.62 -0.38 moles

Mass O = 0 grams

Step 4: Calculate mol ratio

We divide by the smallest amount of moles

C: 0.385 moles / 0.384 = 1

H: 0.384 moles / 0.384 = 1

The empirical formula is CH

This molecular formula is 13 g/mol

We have to multiply the empirical formula by n

n = 78 g/mol / 13 g/mol

n = 6

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3 years ago

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Sonbull [250]

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3 years ago

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romanna [79]

Answer:

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