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padilas [110]
2 years ago
8

At 1.4 atm of pressure a gas has a volume of 111 ML at what pressure will the gas have a volume of 85 ML.

Chemistry
1 answer:
Alona [7]2 years ago
8 0

Answer:

The pressure will be 1, 83 atm

Explanation:

We use Boyle Mariotte's formula: for a given mass of gas at constant temperature, the pressure and volume vary inversely proportionally. We convert the unit ml into L: 111/1000= 0,111 L and 85/1000= 0,085 L.

P1xV1=P2xV2

P2= (P1xV1)/V2=(1,4 atm x 0,111L)/0,085L=<em>1,83 atm</em>

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3) In the reaction below, how many grams of carbon dioxide are produced when iron III
Yanka [14]
<h3>Answer:</h3>

132.03 g

<h3>Explanation:</h3>

<u>We are given;</u>

  • The equation for the reaction as;

Fe₂O₃ + 3CO → 2Fe + 3CO₂

  • Molar masses of CO and CO₂ as 28.01 g/mol and 44.01 g/mol respectively
  • Mass of CO as 84 grams

We are required to calculate the mass of CO₂ that will produced.

<h3>Step 1: Calculate the number of moles of CO</h3>

Moles = Mass ÷ Molar mass

Molar mass of CO = 28.01 g/mol

Therefore;

Moles of CO = 84 g ÷ 28.01 g/mol

                     = 2.9989 moles

                    = 3.0 moles

<h3>Step 2: Calculate the number of moles of CO₂</h3>
  • From the reaction, 3 moles of CO reacts to produce 3 moles of CO₂
  • Therefore; the mole ratio of CO to CO₂ is 1 : 1
  • Hence; Moles of CO = Moles of CO₂

Moles of CO₂ = 3.0 Moles

But; mass = Moles × molar mass

Thus, mass of CO₂ = 3.0 moles × 44.01 g/mol

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Hence, the mass of CO₂ produced from the reaction is 132.03 g

3 0
3 years ago
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