1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lesya692 [45]
2 years ago
7

A scientific law is ___.

Chemistry
1 answer:
Daniel [21]2 years ago
3 0

Answer: a rule that describes a pattern in nature.

Explanation:

You might be interested in
WHO KNOWS HOW TO DO THISSS NEED HELP RN PLS<br><br> Li PO4 + AlF →
Alecsey [184]

Explanation:

Your chemical equation should look like this:

Li3PO4 + AlF3 --> 3LiF + AlPO4

This is the balanced equation for a double-displacement reaction

4 0
3 years ago
Sunlight is composed of energy that is visible to humans and energy that is not visible to humans. Which statement describes how
Vilka [71]

Answer:

A

both forms of energy referred to in the question is light and heat energy

light energy is the visible energy that travels at a known constant speed of 3.0×10^9m/s

while heat energy is the invisible energy that travels in form of radiation at variable speeds

4 0
3 years ago
The pH of a 0.65M solution of hydrofluoric acid HF is measured to be 1.68. Calculate the acid dissociation constant Ka of hydrof
sergey [27]

Answer:

Kₐ = 6.7 x 10⁻⁴

Explanation:

First lets write the equilibrium expression, Ka , for the dissociation of hydrofluoric acid:

HF + H₂O     ⇄   H₃O⁺ +   F⁻

Kₐ = [ H₃O⁺ ] [ F⁻ ] /[ [ HF ]

Since we are given the pH we can calculate the  [ H₃O⁺ ]  ( pH = - log [ H₃O⁺ ] , and because the acid dissociates into a 1: 1  relation , we will also have [F⁻ ]. The  [ HF ] is given in the question so we have all the information that is needed to  compute Kₐ.

pH = -log [ H₃O⁺ ]

1.68 = - log [ H₃O⁺ ]

Taking antilog to both sides of this equation:

10^-1.68 = [ H₃O⁺ ] ⇒ 2.1 X 10⁻²  M= [ H₃O⁺ ]

[ F⁻ ] = 2.1 X 10⁻² M

Solving for Kₐ :

Kₐ = ( 2.1 X 10⁻² ) x  ( 2.1 X 10⁻² ) / 0.65 = 6.7 x 10⁻⁴  

(Rounded to two significant figures, the powers of 10 have infinite precision )

4 0
3 years ago
How many orbitals are available in a “d” orbital configuration?
ratelena [41]

Answer:

e.)5

Explanation:

8 0
3 years ago
A scientist digs up sample of arctic ice that is 458,000 years old. He takes it to his lab and finds that it contains 1.675 gram
Fiesta28 [93]

Answer:

6.70 grams of krypton-81 was present when the ice first formed

Explanation:

Let use the below formula to find the amount of sample

N= N_0(\frac{1}{2})^n

where

n = \frac{t}{t_{\frac{1}{2}}}

here

t =  458,000 years

t_{\frac{1}{2}} = 229,000

\frac{t}{t_{\frac{1}{2}}} = \\frac{ 458,000}{229,000}

n = \frac{t}{t_{\frac{1}{2}}} = 2.000

Now substituting the values

1.675 = N_0(\frac{1}{2})^{2.000}}

1.675 = N_0\times (0.2500)

N_0= \frac{1.675}{0.2500}

N_0=6.70

3 0
3 years ago
Other questions:
  • "which of these nitrogen compounds is in the most reduced state?"
    9·1 answer
  • The nonvolatile, nonelectrolyte cholesterol, C27H46O (386.60 g/mol), is soluble in benzene C6H6. Calculate the osmotic pressure
    10·1 answer
  • The first method of determining the chemical composition of substances in space was to _____.
    6·1 answer
  • At 8:00, the temperature was 6 degrees Celsius (°C). Three hours later, the temperature was -13°C.
    13·2 answers
  • If you have 24 g of Mg burn in 32 g Oz, how many g of MgO are produced?
    15·1 answer
  • What is the shape of a molecule that has 3 atoms bonded to a central atom and no lone pairs of electrons?
    11·2 answers
  • What element is found in liver and is needed to prevent anemia or “tired” blood?
    9·1 answer
  • Which of these objectives do you feel like you've accomplished so far?
    10·1 answer
  • Un paquete de 4.5 kg sube desde el suelo hasta una estantería de 2.8 m de altura. Encuentra el aumento de energía potencial
    6·1 answer
  • When was the "Permian Era"?
    9·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!