Answer:
Michael and Carlos will have the same amount after 7 weeks
Step-by-step explanation:
Assume the total number of baseball cards that Carlos and Michael need to have to be equal is y, and the amount of time in terms of weeks that it will take for this to be achieved is x.
The following expressions can be derived
For Carlos to achieve y, he will need 85 and an addition of 10 per week (x):
y=85+(10x)..........equation 1
For Michael to achieve y, he will need 120 and an addition of 5 per week (x):
y=120+(5x)..........equation 2
Equating equation 1 and 2 to solve for x
85+10x=120+5x
10x-5x=120-85
5x/5=35/5
x=7
Number of weeks it will take Michael and Carlos to have the same amount=x=7 weeks
Time it by the number before hand and you get 8 then 16 then 32 . Think about it it works and it’s a consistent continental
The least square regression equation for the information provided is y = 9.72x - 40.776
<u>The general equation of a regression model can be expressed thus</u>:
Calculating slope, b :
- b = 0.81(177.6 / 14.8) = 9.72
<u>Plugging the values of b, y and x into the equation in other to calculate c</u> :
696 = 9.72(75.8) + c
696 = 736.776 + c
c = 696 - 736.776
c = - 40.776
Therefore, the linear regression model can be expressed as : y = 9.72x - 40.776
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√129 is less than
.

Let us first solve for √129.
➝
➝
Now,
➝
➝
Clearly,
➵
➵
Hence, √129 is less than
.

Answer:
P(X ≥ 1) = 0.50
Step-by-step explanation:
Given that:
The word "supercalifragilisticexpialidocious" has 34 letters in which 'i' appears 7 times in the word.
Then; the probability of success = 7/34 = 0.20588
Using Binomial distribution to determine the probability; we have:

where;
x = 0,1,2,...n and 0 < β < 1
and x represents the number of successes.
However; since the letter is drawn thrice; the probability that the letter "i" is drawn at least once can be computed as:
P(X ≥ 1) = 1 - P(X< 1)
P(X ≥ 1) = 1 - P(X =0)
![P(X \ge 1) = 1 - \bigg [ {^3C__0} (0.21)^0 (1-0.21)^{3-0} \bigg]](https://tex.z-dn.net/?f=P%28X%20%5Cge%201%29%20%3D%20%201%20-%20%5Cbigg%20%5B%20%7B%5E3C__0%7D%20%280.21%29%5E0%20%281-0.21%29%5E%7B3-0%7D%20%5Cbigg%5D)
![P(X \ge 1) = 1 - \bigg [ 1 \times 1 (0.79)^{3} \bigg]](https://tex.z-dn.net/?f=P%28X%20%5Cge%201%29%20%3D%20%201%20-%20%5Cbigg%20%5B%201%20%5Ctimes%201%20%280.79%29%5E%7B3%7D%20%5Cbigg%5D)
P(X ≥ 1) = 1 - 0.50
P(X ≥ 1) = 0.50