To compute the net effect of two waves, we use the superposition principle, and we can call the resultant wave "superposed wave".
We can rewrite the sentence as follows:
"<span>If the above two waveforms were sound waves, we would hear the superposed wave louder. If the above two waveforms were light waves, we would see the superposed wave dimmer."</span>
With these questions, drawing it out would always help, the answer for this would be 90m if you add them all up. If it’s displacement, it would be 30m. But since it’s asking for the distance TRAVELED then it’s 90m
ANSWER: 90m
Answer:
3 m\s Ans .....
Explanation:
Solution:
v = (1.5)(2)
v = 3 m\s <em>A</em><em>n</em><em>s</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>
Answer:
2.7 J
Explanation:
From the question,
The Net work done by the crate = Work done by the crate in moving if through a distance- work done against friction.
W = Fd-F'd.................... Equation 1
Where F = force applied to the crate, d = distance moved by the crate, F' = force of friction
Given: F = 2.4 N, F' = 0.6 N, d = 1.5 m
Substitute these values into equation 1
W = 2.4(1.5)-0.6(1.5)
W = 3.6-0.9
W = 2.7 J