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bazaltina [42]
3 years ago
7

A spherically shaped balloon has a radius of 12.5 m, and is filled with helium. How much extra mass can a cargo lift, assuming t

hat the skin and the cargo of the balloon have a mass of 850 kg? Neglect the buoyant force on the cargo volume itself.(The density of air is 1.29 kg/m3 and the density of helium is 0.179 kg/m3)
Physics
1 answer:
rusak2 [61]3 years ago
8 0

Answer

Radius of the Balloon = 12.5 m

the skin and the cargo of the balloon have a mass = 850 kg

Volume of balloon=\dfrac{4}{3}\pi r^3

                               =\dfrac{4}{3}\ \pi\times 12.5^3

                               =8181.20 m³

Mass the ballon can carry= volume x [density of air-density of helium]

                              =8181.2 x [ 1.29 - 0.179 ]  

                               =9089 kg  

Mass of cargo = 9089 - 850

                        = 8239 kg

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A rope is wrapped around the rim of a large uniform solid disk of mass 325 kg and radius 3.00 m. The horizontal disk is made to
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Answer:

The angular speed is 0.13 rev/s

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From the formula

\tau = I\alpha

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But, the angular acceleration is given by

\alpha = \frac{\omega}{t}

Where \omega is the angular speed

and t is time

Then, we can write that

\tau = \frac{I\omega}{t}

Hence,

\omega = \frac{\tau t}{I}

Now, to determine the angular speed, we first determine the Torque \tau and the moment of inertia I.

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The moment of inertia of the solid disk is given by

I = \frac{1}{2}MR^{2}

Where M is the mass and

R is the radius

∴I = \frac{1}{2} \times 325 \times (3.00)^{2}

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From the question, time t = 2.05 s.

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0.82 rad/s = 0.82/2π rev/s

= 0.13 rev/s

Hence, the angular speed is 0.13 rev/s,

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3 years ago
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