First <u>rewrite the equation</u> in slope intercept form
slope intercept form: y = mx + b [ where m is slope and b is y-intercept ]
<u>comparing</u> with y = mx + b
- slope: -1/4 and y-intercept: 4
x-intercept: ( then y will be 0 )
In order to graph the line
- plot x = 16 on the x-axis coordinate: (16, 0)
- plot y = 4 on the y-axis coordinate: (0, 4)
- Then using a scale/ruler draw a straight line through this points.
Graph:
Answer:
The apples may have costed 0.50 cents each, and she may have bought 10, which would result in her paying 10 dollars, and receiving 5 dollars in change.
Step-by-step explanation:
Multiply 10 (the amount she gave to the cashier) by 0.50%, it equals 5, so that's how much she paid, and since she gave a 10 dollar bill, she should get 5 dollars in change.
T^T
Answer: 0.0084
Step-by-step explanation:
Let p be the population proportion of the creatures in Wonderland are anthropomorphic animals.
As per given, p = 0.70
Sample size : n=120
Let 
be the sample proportion of the creatures are anthropomorphic animals.
Now, required probability :
![P(\hat{p}>0.80)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.80-0.70}{\sqrt{\dfrac{0.70\times (1-0.70)}{120}}})\\\\P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.10}{\sqrt{\dfrac{0.70\times 30}{120}}})\\\\ =P(Z>\dfrac{0.10}{\sqrt{0.00175}})\ \ \ \ \ [Z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}]\\\\ =P(Z>\dfrac{0.10}{0.04183})\\\\\=P(Z>2.39)\\\\=1-P(Z\leq2.39)\\\\=1- 0.9916= 0.0084](https://tex.z-dn.net/?f=P%28%5Chat%7Bp%7D%3E0.80%29%3DP%28%5Cdfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%3E%5Cdfrac%7B0.80-0.70%7D%7B%5Csqrt%7B%5Cdfrac%7B0.70%5Ctimes%20%281-0.70%29%7D%7B120%7D%7D%7D%29%5C%5C%5C%5CP%28%5Cdfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%3E%5Cdfrac%7B0.10%7D%7B%5Csqrt%7B%5Cdfrac%7B0.70%5Ctimes%2030%7D%7B120%7D%7D%7D%29%5C%5C%5C%5C%20%3DP%28Z%3E%5Cdfrac%7B0.10%7D%7B%5Csqrt%7B0.00175%7D%7D%29%5C%20%5C%20%5C%20%5C%20%5C%20%5BZ%3D%5Cdfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%5D%5C%5C%5C%5C%20%3DP%28Z%3E%5Cdfrac%7B0.10%7D%7B0.04183%7D%29%5C%5C%5C%5C%5C%3DP%28Z%3E2.39%29%5C%5C%5C%5C%3D1-P%28Z%5Cleq2.39%29%5C%5C%5C%5C%3D1-%200.9916%3D%200.0084)
Hence, the probability that more than 80% of the sampled inhabitants are animals= 0.0084
I am not sure, but I hink it is C!
