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TEA [102]
3 years ago
13

The average number of stars in a galaxy is about 5x10^11 and the total number of galaxies is about 5.2x10^9. what is the total n

umber of stars in the universe
Mathematics
1 answer:
Arisa [49]3 years ago
4 0

Answer:

2.6 x 10^21

Step-by-step explanation:

Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the  10   If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

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A. Two orders for birthday parties come in and you are responsible for getting the order ready. Both orders ask for 192 ounces o
Colt1911 [192]

Answer:

64

Step-by-step explanation:

this should be easy cause the 64 is bigger, so the parts are smaller. 192 divided by 64 is 3. 192 divided by 12 is 16. multiply, Yada yada… you get 64 is better!

7 0
3 years ago
How do you do monomial
iris [78.8K]

Answer:

Multiplying a Monomial by a Monomial. When multiplying a monomial by a monomial, we multiply the coefficients together and tack on the variables at the end (usually in alphabetical order). When multiplying two of the same variables, add the exponents. Remember that the exponent on x is an invisible 1.

Step-by-step explanation:

Hope this helps


4 0
3 years ago
Solve the following equation for d.<br><br> m+1/6rd = 7
Amanda [17]

Answer: d = 42/r - 6m/r

Step-by-step explanation: Isolate the variable by dividing each side by factors that don't contain the variable.

8 0
3 years ago
The combined age of three relatives is 120 years. James is three times the age of Dan, and Paul is two time the sum of the ages
BaLLatris [955]

Answer:

Step-by-step explanation:

Let x represent Dan's age

3x be James'age

Paul 2(3x+x)=6x+2x

Suming all ages

x+3x+6x+2x=120

Solving for x

12x=120

x=10 (Dan's age)

3×=30 (James'age)

6×+2×=80(Paul's age)

8 0
4 years ago
You have 400 feet of fencing to enclose a rectangular plot. Find the length and width of the plot that will maximize the area. W
3241004551 [841]
Well, we can denote L and W for the length and width respectively. Lets say the A is the area, we have: 1. A=(L × W) as well as 2. 2(L+W)=400. We rearrange the second equation to get 3. W=200-L. From this, we can see that 0<L<200. Substitute the third equation into the first to get A=(200L-L²). put this formula into the scientific calculator and you will find a parabola with a maximum. That would be the maximum area of the enclosed area. Alternatively, we can say that L is between 0 and 200 when the area equals 0. (The graph you find will be  area against length). As the maximum is generally found halfway, we substitute 100 into the equation and we end up with 10000.

Hope this helps.
6 0
3 years ago
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