Question

A teacher is making identical activity packets using 92 crayons and 23 sheets of paper. What is the greatest number of packets the teacher can make with no item left over?

Answer 1

92 and 23 sheet of paper.
4  to 1  4 crayons to 1 sheet of paper

Answer 2

Factor both numbers:

1. 92=2·46=2·2·23;

2. 23 is prime number.

Then the greatest common factor GCF(92, 23)=23.

This means that teacher can make 23 packets, each of them will contain 4 crayons and 1 sheet.

Answer: 23 packets.