A teacher is making identical activity packets using 92 crayons and 23 sheets of paper. What is the greatest number of packets t
he teacher can make with no item left over?
2 answers:
92 and 23 sheet of paper.
4 to 1 4 crayons to 1 sheet of paper
Factor both numbers:
1. 92=2·46=2·2·23;
2. 23 is prime number.
Then the greatest common factor GCF(92, 23)=23.
This means that teacher can make 23 packets, each of them will contain 4 crayons and 1 sheet.
Answer: 23 packets.
You might be interested in
I’m can’t freakin stay up I need to sleep and I need to get 4 papers done for my portfolio I can’t help but I wish you luck
Answer:
I'm pretty sure its 1/4
Step-by-step explanation:
set up the composite function and evaluate
Two million, nine thousand three hundred forty five
Answer
14cm
Step-by-step explanation:
(4)2 + 7= 15.
15-7=8.
I would say that number is 4 because 4+4= 8, and 8+7 =15.