A teacher is making identical activity packets using 92 crayons and 23 sheets of paper. What is the greatest number of packets t
he teacher can make with no item left over?
2 answers:
92 and 23 sheet of paper.
4 to 1 4 crayons to 1 sheet of paper
Factor both numbers:
1. 92=2·46=2·2·23;
2. 23 is prime number.
Then the greatest common factor GCF(92, 23)=23.
This means that teacher can make 23 packets, each of them will contain 4 crayons and 1 sheet.
Answer: 23 packets.
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