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aleksandr82 [10.1K]
3 years ago
15

Advances in technology have enabled scientists and researchers to better study the evolutionary relationships between species. M

atch each field of study to its description. embryology developmental biology molecular biology comparative anatomy the study of the anatomy of an organism to explain evolutionary similarity arrowRight the study of similarities in embryos of organisms to find common connections arrowRight the analysis and comparison of DNA to better understand relationships between species arrowRight the study of life cycles of organisms to find common stages arrowRight
Biology
1 answer:
padilas [110]3 years ago
5 0

Answer:

Embryology: the study of similarities in embryos of organisms to find common connections

Developmental biology:  the study of life cycles of organisms to find common

Molecular biology: the analysis and comparison of DNA to better understand relationships between species

comparative anatomy: the study of the anatomy of an organism to explain evolutionary similarity

Explanation:

Embryology can be described as the branch of biology in  which studies about the sex cells, the process of fertilization and the development of the fetus or embryo are made. The similarities between the embryos show evolutionary history among different organisms.

Developmental biology can be described as the branch of biology in which studies are made about the processes of growth and developmental procedures about organisms. Organisms belonging to different groups can also show developmental similarities if they have a common ancestor.

Molecular biology is the branch of biology which is related to the study of life on molecular level. At this level, similarities between the genome of organisms can be checked for evolutionary histories.

Comparative anatomy: It is the branch of biology in which organisms are studies based on the similarities and differences in their structures.

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Answer:

a is the middle gene.

Distance [b-a]= 24.7 mu

Distance [a-c]= 15.8 mu

Distance [b-a} = 40.5 mu

Explanation:

A homozygous wild-type female drosophila (a⁺b⁺c⁺/a⁺b⁺c⁺) is crossed with a homozygous recessive male (abc/abc). <u>The order of the genes here is arbitrary. </u>

The F1 is heterozygous for the three genes (a⁺b⁺c⁺/abc). The F1 females were test crossed (crossed with abc/abc males).

The F2 shows the following phenotypic ratios:

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Total = 1000

The male parent is homozygous recessive for the 3 genes, so the observed phenotypes of the offspring correspond to the gametes received from the mother.

Recombination during meiosis is a rare event, so the most abundant gametes are always the parentals:  a⁺b⁺c⁺ and abc.

The least abundant gametes, following the same logic, are the double crossovers (DCO): a⁺bc and ab⁺c⁺.

<h3><u>1st. Determine the gene order</u></h3>

Compare the parental and the DCO gametes. The allele that is switched corresponds to the middle gene. In this case, gene a is in the middle of the other two.

<h3><u>2nd Determine the single crossover gametes</u></h3>

The F1 mother that generated all 8 types of gametes had the genotype b⁺a⁺c⁺/bac (correct order of genes).

  • The single crossover (SCO) gametes resulting from recombination between genes b and a are b⁺ac and ba⁺c⁺.
  • The single crossover (SCO) gametes resulting from recombination between genes a and c are b⁺a⁺c and bac⁺.
<h3><u>3) Calculate the recombination frequencies between genes </u></h3>

Recombination frequency (RF) = #Recombinants/Total progeny

  • RF [b-a]= (102+112+18+15)/1000= 0.247
  • RF [f-br]= (66+59+18+15)/1000= 0.158
<h3><u /></h3><h3><u>4) Calculate the distance in map units </u></h3>

Distance (mu) = RF x 100

Distance [b-a]= 0.247 × 100 = 24.7 mu

Distance [a-c]= 0.158 × 100 = 15.8 mu

Distance [b-a} = 24.7 mu + 15.8 mu = 40.5 mu

<h3><u>The gene map therefore looks like: </u></h3>

b------------24.7 mu--------------------------a---------15.8 mu-----------c

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