Answer:
h(8q²-2q) = 56q² -10q
k(2q²+3q) = 16q² +31q
Step-by-step explanation:
1. Replace x in the function definition with the function's argument, then simplify.
h(x) = 7x +4q
h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q
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2. Same as the first problem.
k(x) = 8x +7q
k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q
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Comment on the problem
In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...
h(8q² -2q) = 56q² -14q +4z
and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.
In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.
Answer:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
Step-by-step explanation:
Liquid R has a mass of of 1 kg at a temperature of 30°c kept in a refrigerator to freeze . Given the specific heat capacity is 300 J kg-¹ °c-1 and the freezing point is 4°c . Calculate the heat release by liquid R.
Answer:
4x^2+15
Step-by-step explanation:
1. multiply whole parenthesis by power of 2
2. gets you 4(x^2+4)-1
3.Multply and it gets you 4x^2+16-1 so it would be 4x^2+15 for your answer
4. throw that into your calculator and make sure its not on radian mode and then press graph
Answer:
n = (m-1)/(4-g)
Step-by-step explanation:
m= 4n-gn+1
Subtract 1 from each side
m-1= 4n-gn+1-1
m-1 = 4n -gn
Factor out n
m-1 = n(4-g)
Divide each side by (4-g)
(m-1)/(4-g) = n(4-g)/(4-g)
(m-1)/(4-g) = n
n = (m-1)/(4-g)
Move all terms not containing x to the right side of the inequality.
x ≥ 13
Hope this helps! :)
and Happy Holloween!
~Zane
