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MrRa [10]
4 years ago
8

What is six times six take away for plus nine​

Mathematics
1 answer:
vladimir2022 [97]4 years ago
7 0

Hello, thanks for using Brainly!

We are solving 6x6-4+9.

We will do three steps in this case.

First is 6x6, 6x6 is 30.

So now we must keep in our head we have 30 as our first number.

Now, let's -4 from 30. 30-4 is 26.

We just did step 2. Boom!

So, we have 26 as our second number. Let's do our third step.

If we have 26, we need to add 9 to that. To quickly find that we know that 26+10 is 36. That is adding ten, we need 9 so minus 1 from 36 we get 35.

Our final answer is 35.

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4x=5x-3
+3 +3

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-4x -4x

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8 0
4 years ago
Pls pls pls pls pls help
raketka [301]

Answer:38x-34

Step-by-step explanation:

f(x)=x^2+3x-7

g(x)=5x-3

We multiply the entire F equation times two, (x^2+3x-7)*4=

(4x^2+12x-28)

Now the entire g equation by 2, (5x-3)*2

(10x-6)

Now we add both equation

(4x^2+12x-28)+(10x-6)

(4x^2+22x-34)

(4x*4x+22x-34)

(16x+22x-34)

38x-34

Hopefully this is correct :)))

7 0
3 years ago
Your uncle took you to the Nike store to get the latest Jordan's. The cost of the Jordan's are $112.99. Your uncle gives the cas
Oksana_A [137]

Answer:

B. $96.04

Step-by-step explanation:

112.99 - 15%=96.04

7 0
3 years ago
Read 2 more answers
What is the area of rhombus ABCD? Enter your answer in the box. Do not round at any steps. put the answer in units²
AlladinOne [14]

Answer:

Therefore the Area of Rhombus ABCD is 36 unit².

Step-by-step explanation:

Given:

ABCD is a Rhombus

A = (-1,0)

B = (5,-3)

C = (-1,-6)

D = (-7 ,-3)

To Find:

Area of Rhombus ABCD = ?

Solution:

We know that Area of Rhombus is given as

\textrm{Area of Rhombus}=\dfrac{1}{2}\times d_{1}\times d_{2}

Where ,

d₁ and d₂ are the Diagonals.

We have,

Diagonals as AC and BD,

Using Distance Formula we get

l(AC) = \sqrt{((x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2} )}

Substituting coordinates A and C we get

l(AC) = \sqrt{((-1-(-1))^{2}+(-6-0)^{2} )}=\sqrt{36}\\l(AC)=6\ unit

Similarly for BD we have,

l(BD) = \sqrt{((5-(-7))^{2}+(-3-(-3))^{2} )}=\sqrt{144}\\l(BD)=12\ unit

Now Substituting AC and BD in Formula we get

\textrm{Area of Rhombus}=\dfrac{1}{2}\times AC\times BD

\textrm{Area of Rhombus}=\dfrac{1}{2}\times 6\times 12=36\ unit^{2}

Therefore the Area of Rhombus ABCD is 36 unit².

6 0
3 years ago
Hi I need some help...<br> -6y + 17 = 3y -10
prisoha [69]

Answer:

y=3

Step-by-step explanation:

Solve by subtracting

-6y + 17 = 3y -10\\-6y=3y-27\\-9y=-27\\

Divide.

-9y=-27\\y=-27/-9\\y=3

5 0
3 years ago
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