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MrRa [10]
3 years ago
8

What is six times six take away for plus nine​

Mathematics
1 answer:
vladimir2022 [97]3 years ago
7 0

Hello, thanks for using Brainly!

We are solving 6x6-4+9.

We will do three steps in this case.

First is 6x6, 6x6 is 30.

So now we must keep in our head we have 30 as our first number.

Now, let's -4 from 30. 30-4 is 26.

We just did step 2. Boom!

So, we have 26 as our second number. Let's do our third step.

If we have 26, we need to add 9 to that. To quickly find that we know that 26+10 is 36. That is adding ten, we need 9 so minus 1 from 36 we get 35.

Our final answer is 35.

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Answer:

77.  \cot^{6} x = \cot^{4} x \csc^{2}x - \cot^{4} xProved

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Step-by-step explanation:

77. Left hand side

= \cot^{6} x

= \cot^{4} x \times \cot^{2} x

= \cot^{4}x [\csc^{2}x - 1]  

{Since we know, \csc^{2} x - \cot^{2}x = 1}

= \cot^{4} x \csc^{2}x - \cot^{4} x  

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78. Left hand side

= \sec^{4}x \tan^{2} x

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{Since \sec^{2}x - \tan^{2}x = 1}

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= Right hand side (Proved)

79. Left hand side  

= \cos^{3} x\sin^{2} x

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{Since \sin^{2}x + \cos^{2} x = 1}

= [\sin^{2}x - \sin^{4}x] \cos x

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80. Left hand side  

= \sin^{4}x - \cos^{4}x

= [\sin^{2}x + \cos^{2}x]^{2} - 2\sin^{2} x \cos^{2}x

{Since \sin^{2}x + \cos^{2} x = 1}

= 1 - 2\cos^{2} x[1 - \cos^{2}x ]

= 1 - 2\cos^{2}x + 2 \cos^{4} x

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Answer:

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