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user100 [1]
3 years ago
12

How does the shape of the earth affect our view of stars

Biology
1 answer:
Mrac [35]3 years ago
7 0
The shape of the earth affects our view of the stars because since we are shaped a sphere, we get more of a view of many different stars and not much is blocking our view
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An Earth scientist is testing how vanous soil mixtures affect plant growth. She begins with 10 soil types. For each mixture, she
nevsk [136]

The correct answer to my knowledge would be 45.

Assuming that the 10 soils are each represented by A, B, C, D, E, F, G, H, I, J.

A can combine with 9 others as: AB AC AD AE A F AG AH AI AJ

B can combine as: BC BD BE BF BG BH BI BJ

C as: CD CE CF CG CH CI CJ

D as: DE DF DG DH DI DJ

E as: EF EG EH EI EJ

F as: FG FH FI FJ

G as: GH GI GJ

H as: HI HJ

I as: IJ

Once you add all the combinations together, you get 45.

Hoping this helped you!

3 0
3 years ago
The offspring of a sexually-reproducing organism receives *
arlik [135]

Answer:

Lack of ability to adapt to changes in the envrionment

Explanation:

Asexual reproduction produces offspring that are genetically identical to the parent and no DNA is mixed, so they would not be able to adapt because there would be no genetic variation.

7 0
2 years ago
If the heterozygous, Ww, is crossed with a homozygous dominant, WW, then the probability of having a homozygous. Recessive offsp
eduard
A. 0% is the answer
5 0
3 years ago
Which type of protist is photosynthetic and unicellular with a silica shell?
Len [333]
The answer is C .......
7 0
2 years ago
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Given the parents AABBCc × AabbCc, assume simple dominance for each trait and independent assortment. What proportion of the pro
Anit [1.1K]

Answer:

3/4

Explanation:

If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.

<h3><u>Gene A</u></h3>

AA x Aa

  • F1 genotypes: 1/2 AA, 1/2 Aa
  • F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>

BB x bb

  • F1 genotypes: 1 Bb
  • F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>

Cc x Cc

  • F1 genotypes:  1/4 CC, 2/4 Cc, 1/4 cc
  • F1 phenotypes: 3/4 C, 1/4 cc

We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:

<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>
6 0
3 years ago
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