Answer:
C)
Explanation:
M1V1 = M2V2
40.0ml*0.25M = M2*50.0ml
M2 = 40.0*0.25/50.0 = 0.20 M
The agar plate with the most countable colonies should be determined by using a colony forming unit (CFU) calculator.
<h3>What is a colony?</h3>
A colony can be defined as a group of visible mass of microorganisms such as bacteria, fungi, that originated (cultured) from a single-mother cell and are grown on a solid agar medium.
In order to determine the most countable colonies, we have to count the total number of colonies by using a hemacytometer and then use a colony forming unit (CFU) calculator to determine the cfu/mL.
<u>Note:</u> You should choose a dilution factor based on the total number of colonies contained in the agar plate.
Finally, input the correct dilution factor into the colony forming unit (CFU) calculator to determine which agar plate has the most countable colonies.
Read more on dilution factor here: brainly.com/question/24881505
I think the answer is C , more dense
The correct option is NONE OF THE ABOVE. T
The bases in the options above such as NaOH and KOH are strong hydroxides and they are strong bases. Examples of hydroxides that are weak bases are iron hydroxide, ammonium hydroxide, etc.
Answer:
Q = 940.5 j
Explanation:
Given data:
Mass of iron = 95 .00 g
Initial temperature = 36.0°C
Final temperature = 58°C
Heat lost = ?
Solution:
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Specific heat capacity of iron = 0.450 j/g.°C
ΔT = T2-T1
ΔT = 58°C-36.0°C
ΔT = 22°C
Q = m.c. ΔT
Q = 95.00 g × 0.450 j/g.°C × 22°C
Q = 940.5 j