Answer:
0.32M
Explanation:
<u>Step 1:</u> Balance the reaction
K2CO3 + Ba(NO3)2 ⇔ KNO3 + BaCO3
We have a 20 mL 0.2 M K2CO3 and a 30mL 0.4M Ba(NO3)2 solution
SinceK2CO3 is the limiting reactant, there will remain Ba(NO3)2 after it's consumed and produced KNO3 + BaCO3
<u>Step 2: </u>Calculate concentration
To find the concentration of the barium cation we use the following equation:
Concentration = moles of the <u>solute</u> / volumen of the <u>solution</u>
<u />
<u>[Ba2+] </u> = (20 * 10^-3 * 0.2M + 30 * 10^-3 * 0.4M) / ( 20 + 30mL) *10^-3
[Ba2+] = 0.32 M
The concentration of Barium ion in solution is 0.32 M
Answer: 0.5 kg
Explanation:
Force of launched skyrocket = 10 N
Acceleration of skyrocket = 20 m/s squared (i.e 20m/s^2)
Mass of the skyrocket = ?
Recall that Force is the product of the mass of an object by the acceleration by which it moves.
i.e Force = Mass x Acceleration
10N = Mass x 20m/s^2
Mass = (10N/20m/s^2)
Mass = 0.5 kg
Thus, the mass of this skyrocket is 0.5 kilograms
Answer:
[HOCH₂CH₂OH] = 24.1 m
Explanation:
Ethylene glycol → HOCH₂CH₂OH
60% by mass means that 60 g of ethylene glycol are contained in 100 g of solution.
Solution mass = Solute mass + Solvent mass
100 g = 60 g + Solvent mass
Solvent mass = 40 g
Molality are the moles of solute contained in 1kg of solvent.
We determine the moles of solute → 60 g . 1mol/62 g = 0.967 moles
We convert the mass of solvent from g to kg → 40 g . 1kg/1000 g = 0.04 kg
Molality → 0.967 mol / 0.04 kg = 24.1 m
I think the answer is the moon
