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ludmilkaskok [199]
2 years ago
12

PLZ HELP ME..ITS MY TEST

Chemistry
2 answers:
Sati [7]2 years ago
8 0

Answer: Oxidizing Agent

Explanation: When Cr is reduced (gains electrons), it is oxidizing the other element (removing its electrons) so it is the oxidizing agent.

artcher [175]2 years ago
4 0
Oxidizing agent would be the best answer choice i would choose
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Which product is used on the natural nail prior to product application to assist in adhesion and serves to chemically bond the e
ira [324]

The product that is used on the natural nail prior to application to assist in adhesion and serves to chemically bond the enhancement product to the natural nail is known as nail primer.

<h3>What is a nail primer?</h3>

A nail primer is a chemical agent used in esthetic centers before applying a colored polish to the nails and serves as an adhesive product.

The nail primers are also very useful for improving the cleaning efficiency of the product before its application.

Nail care products include different types of chemical formulations such as, for example, creams that reinvigorate the cuticle.

In conclusion, the chemical formulation employed on the natural nail that is capable of enhancing and also assisting adhesion is called the nail primer.

Learn more about nail esthetic products here:

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8 0
2 years ago
What is the molarity of solution prepared by dissolving 11.75 g of KNO3 in enough water to produce 2.00 L of solution?
zysi [14]
The molar mass of the compound potassium nitrate, KNO3 is equal to 101.1032 g/mol. Then, we determine the number of moles present in the given amount,
                       n = 11.75g / (101.1032 g/mol) = 0.116 mol
Then, molarity is calculated by dividing the number of moles by the volume of the solution. The answer is therefore 0.058 M. 
3 0
3 years ago
Which of the following is NOT true about a C-14 atom?
romanna [79]

Answer:

option C. it contain 6 neutrons.

Explanation:

7 0
2 years ago
Which metal in Period 5 is very reactive and has two valence electrons in each atom? rubidium (Rb) strontium (Sr) zirconium (Zr)
vladimir1956 [14]
<h3>Answer:</h3>

           Strontium (Sr)

<h3>Explanation:</h3>

                        The condition given in statement is the presence of two valence electron. Hence, first we found the electronic configuration of given atoms as follow;

                       Rubidium                         [Kr] 5s¹

                      Strontium                        [Kr] 5s²

                       Zirconium                         [Kr] 4d² 5s²

                      Silver                                 [Kr] 4d¹⁰ 5s¹

From above configurations it is cleared that only Strontium and Zirconium has two electrons in its valence shell.

We also know that s-block elements are more reactive than transition elements due to less shielding effect in transition elements hence, making it difficult for transition metals to loose electrons as compared to s-block elements. Therefore, we can conclude that Strontium present in s-block with two valence electrons is the correct answer.

4 0
3 years ago
Read 2 more answers
Ralph and Sheila are at a construction site and they are stacking bricks. The diagram above shows the bricks before they touch.
aliya0001 [1]

Answer: Sheila's top brick will be cooler than Ralph’s top brick, because Sheila’s started with more total energy, so less energy had to transfer for both her bricks to reach the same total energy.

Explanation:

6 0
2 years ago
Read 2 more answers
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