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3 years ago

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The Moon moves around the Earth in an approximately circular orbit, going once around in approximately 27.3 days. The moon orbits quite fast: it moves about 0.5 degrees per hour in the sky. So, its average movement in a day is around 13 degrees. 5 days x 13 degrees is approximately 65 degrees.

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A molecule of an organic compound contains at least one atom of

Mila [183]

A molecule of an organic compound contains at least one atom of "(1) carbon". This is referred to as organic chemistry, since all living matter is carbon-based.

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3 years ago

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The reaction A → products is first order. If the initial concentration of A is 0.646 M and, after 72.8 seconds have elapsed, the

mario62 [17]

Answer: 0.00867 moldm-3

Explanation:

Since the reaction is 1st order,

Rate of reaction=∆[A]÷t

0.646-0.0146/72.8= 0.00867

Remember that in a first order reaction, the rate of reaction depends on change in the concentration of only one of the reaction species, A in the problem above.

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3 years ago

What type of bond is formed between the oxygen atom of one water molecule and the hydrogen atom of another water molecule?

zysi [14]

The bond formed between oxygen atom of 1 water molecule with the hydrogen atom of another water molecule is called 'hydrogen bond'.
Hope this helps!

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4 years ago

A) A volume of 100 mL of 1.00 M HCl solution is titrated with 1.00 M NaOH solution. You added the following quantities of 1.00 M

Wewaii [24]

Answer:

i) 5.00 mL of 1.00 M NaOH: before the equivalence point

ii) 50.0 mL of 1.00 M NaOH: before the equivalence point

iii) 100 mL of 1.00 M NaOH: at the equivalence point

iv) 150 mL of 1.00 M NaOH: after the equivalence point

v) 200 mL of 1.00 M NaOH: after the equivalence point

Explanation:

1. First calculate the number of mol acid in the 100 mL of 1.00 M HCl solution.

Equation:

Molarity = numbrer of moles of solute / volume of the solution in liters.

Thus, you need to convert each volume from mL to liters, which is done dividing by 1,000.

Naming M the molarity, n the number of moles of solute (acid or base), and V the volume in liters:

$M=n/v\implies n=M\times V=1.00M\times 0.100L=0.100mol$

2. Now calculate the number of moles of NaOH for every condition (addition)

i) 5.00 mL of 1.00 M NaOH

$n=0.00500liter\times 1.00M=0.00500molNaOH$

Since the number of moles of NaOH added (0.00500mol) is less than the number of moles of acid in the solution (0.100mol), this is before equivalence point.

ii) 50.0 mL of 1.00 M NaOH

$n=0.0500liter\times 1.00M=0.0500molNaOH$

Since the number of moles of NaOH added (0.0500mol) is less than the number of moles of acid in the solution (0.100mol), this is before equivalence point.

iii) 100 mL of 1.00 M NaOH

$n=0.100liter\times 1.00M=0.100molNaOH$

Since the number of moles of NaOH added (0.100mol) is equal to the number of moles of acid in the solution (0.100mol), this is at the equivalence point.

iv) 150 mL of 1.00 M NaOH

$n=0.150liter\times 1.00M=0.150molNaOH$

Since the number of moles of NaOH added (0.150mol) is greater than the number of moles of acid in the solution (0.100mol), this is after the equivalence point.

v) 200 mL of 1.00 M NaOH

This is more volume of NaOH, then this is also after the equivalence point.

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3 years ago

What five SI base units are commonly used in chemistry?

Rashid [163]

Five base SI units that are commonly used in Chemistry; are
1.Metre (m)
2. Kilogram(kg)
3. seconds(s)
4.Kelvins (k)
5. Moles (mol)

3 0

3 years ago

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