Answer:
<h3>The answer is 0.75 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass = 90 g
volume = 120 mL
We have
We have the final answer as
<h3>0.75 g/mL</h3>
Hope this helps you
The volume of CO2 at STP =124.298 L
<h3>Further explanation</h3>
Given
Reaction
4 KMnO4, +4 C3H5(OH)5, -7K2CO3, + 7 Mn2O3, +5 CO2, + 16 H2O
701,52 g of KMnO4
Required
volume of CO2 at STP
Solution
mol KMnO4 (MW=158,034 g/mol) :
mol = mass : MW
mol = 701.52 : 158.034
mol = 4.439
mol CO2 from equation : 5/4 x mol KMnO4 = 5/4 x 4.439 = 5.549
At STP 1 mol = 22.4 L, so for 5.549 moles :
=5.549 x 22.4
=124.298 L
<span>Biotic and Abiotic Factors Form Ecosystems. In a healthy forest community, interacting populations might include birds eating insects, squirrels
eating nuts from trees, mushrooms growing from decaying leaves or bark,
and raccoons fishing in a stream. In addition to how individuals in a
population interact with each other, let me know if it helps :)</span>
