<span>We can use the heat
equation,
Q = mcΔT </span>
Where Q is the amount of energy transferred (J), m is
the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature
difference (°C).
Let's say
heat gained by 100.10 g of water at 10°C = Q₁
heat lost from 100.0 g of water at 60 °C = Q₂
Final temperature of the mixture = T
<span> Since, there is no heat is lost to the surroundings,
Q</span>
₁ = Q₂ mc(T - 10) = mc(60 - T)
Since, m is same for both sides (100.0 g) and c is a constant for the water, we can cut off m and c from both sides. Then,
(T - 10) =(60 - T)
2T = 60 + 10
2T = 70
T = 35 °C
Hence, final temperature of water is T = 35 °C.
Answer:
Explanation:
Hello!
In this case, for this problem, it is possible to use the thermodynamic definition of the Gibbs free energy:
Whereas G, H and S can be assumed as constant over T; thus, we can calculate H at 135.4 °C:
Now, we can calculate the Gibbs free energy at 12.7 °C as shown below:
Best regards!
1. “what forms of energy conversions occur during the process of photosynthesis? (How does energy transform?)
2. What is missing from the food web but is essential to maintain equilibrium?
A. Soil
B.water
C. Decomposers
D. Oxygen
Answer: Christine Herman & L.G Wade Jr., "2010". Organic Chemistry: Reaction of Alkane, 7e, Pearson Education, Radford University, Radford, VA.
Explanation:
This is an edited book. The Harvard reference style was used in the following order:
Authors name
Year of publication
Title
Edition
Publisher
Place of publication.
Note that the title of book should be italicized with capitalization of first word.
Answer:
A ) New rocks floating to the surface of the crust.
TRUST