Potassium Iodide or KI is an ionic compound and dissolves to water since the two are polar substances. Like dissolves like. As KI is dissolved into water, the KI molecules dissociates into ions, the K+ and I- ions. Water molecules can stabilize these ions. The K+ ions attracts the negative side of H2O molecules which is the oxygen side while the I- ions attracts the positive side of H2O molecules or the hydrogen side.

8 0

3 years ago

I need help with like 35 questions anyone willing to help please let me know I have discord

posledela

Answer and Explanation:

The molar mass of a substance is all of the weights from the elements combined.

So, we have the elements

CU, S, and $O_{4}$

CU has a mass is 65

S mass is 32

O has a mass of 16, but there's 4 atoms of O, so we do 16 times 4, which is 64.

Now we add.

65 + 32 + 64 is 161.

So, the answer is 160, or answer choice A.

#teamtrees #PAW (Plant And Water)

3 0

3 years ago

How many moles and numbers of ions of each type are present in the following aqueous solution? 63.1 mL of 1.85 M magnesium chlor

Alexxandr [17]

Answer:

We have 0.117 moles Mg^2+ and 0.234 moles Cl-

The number of Mg^2+ ions = 7.04 *10^22 ions

The number of Cl- ions = 1.4*10^23 ions

Explanation:

Step 1: Data given

Volume of magnesium chloride = 63.1 mL

Concentration of solution = 1.85 M

Step 2: Calculate moles MgCl2

Moles MgCl2 = concentration * volume

Moles MgCl2 = 1.85 M * 0.0631 L

Moles MgCl2 = 0.117 moles

Step 3: Calculate moles of ions

MgCl2 → Mg^2+ + 2Cl-

For 1 mol MgCl2 we have 1 mol Mg^2+ and 2 moles Cl-

For 0.117 moles MgCl2 we have 0.117 moles Mg^2+ and 2*0.117 = 0.234 moles Cl-

The number of Mg^2+ ions = 0.117 * 6.022 *10^23 = 7.04 *10^22 ions

The number of Cl- ions = 1.4*10^23 ions

4 0

4 years ago