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1 year ago

the reaction a(g) ⇌ b(g) has an equilibrium constant that is less than one. what can you conclude about ∆g° for the reaction?

Chemistry

1 answer:

-Dominant- [34]1 year ago

4 0

For this reaction: ΔG⁰>0.

Balanced chemical reaction A(g) ⇌ (g)

ΔG° indicates that all reactants and products are in their standard states.

ΔG° = R·T·lnK.

ΔG° is Gibbs free energy

T is the temperature on the Kelvin scale

R is the ideal gas constant

The equilibrium constant (K) is the ratio of the partial pressures or the concentrations of products to reactants.

Gibbs free energy (G) determines if reaction will proceed spontaneously, nonspontaneously or in equilibrium processes.

If K < 1, than ΔG° > 0.

Reactants (in this example A) are favored over products (in this example B) at equilibrium.

More about equilibrium: brainly.com/question/25651917:

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Given these reactions, where X represents a generic metal or metalloid 1 ) H 2 ( g ) + 1 2 O 2 ( g ) ⟶ H 2 O ( g ) Δ H 1 = − 241

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Answer : The enthalpy of the given reaction will be, -1048.6 kJ

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According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

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$XCl_4(s)+2H_2O(l)\rightarrow XO_2(s)+4HCl(g)$ $\Delta H=?$

The intermediate balanced chemical reactions are:

(1) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(g)$ $\Delta H_1=-241.8kJ$

(2) $X(s)+2Cl_2(g)\rightarrow XCl_4(s)$ $\Delta H_2=+461.9kJ$

(3) $\frac{1}{2}H_2(g)+\frac{1}{2}Cl_2(g)\rightarrow HCl(g)$ $\Delta H_3=-92.3kJ$

(4) $X(s)+O_2(g)\rightarrow XO_2(s)$ $\Delta H_4=-789.1kJ$

(5) $H_2O(g)\rightarrow H_2O(l)$ $\Delta H_5=-44.0kJ$

Now reversing reaction 2, multiplying reaction 3 by 4, reversing reaction 1 and multiplying by 2, reversing reaction 5 and multiplying by 2 and then adding all the equations, we get :

(1) $2H_2O(g)\rightarrow 2H_2(g)+O_2(g)$ $\Delta H_1=2\times 241.8kJ=483.6kJ$