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3 years ago

12

Find the probability that a data value picked at random from a normally distributed population will have a standard score that c

orresponds to the following:
Less than 3.00

1 answer:

DerKrebs [107]3 years ago

8 0

P(z < 3)
From the normal distribution table,
P(z < 3) = 0.9987

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2 years ago

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2 years ago

Three numbers are in the ratio 3:9:10. If 10 is added to the last number, then the three numbers form an arithmetic progression.

MrRa [10]

Answer:

<em> The numbers are 6, 18, and 30 </em>

Step-by-step explanation:

If the three numbers are in the ratio of 3:9:10,

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<em>If 10 is added to the last number to form an arithmetic progression</em>

<em>Then, 3x 9x (10x+10) are the progression</em>

The common difference of an arithmetic progression (d) = T₂ - T₁ = T₃ - T₂

T₂-T₁ = T₃ - T₂ .............. Equation 1

Where T₁ = first term of the progression, T₂ = Second term of the progression, T₃ = third term of the progression

<em>Given: T₁ = 3x, T₂ = 9x, T₃ = 10x +10</em>

<em>Substituting these values into equation 1</em>

<em>9x-3x = (10x+10)-9x</em>

<em>Solving the equation above,</em>

<em>3x = 10+x</em>

<em>3x-x = 10</em>

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3 years ago

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1 year ago

Read 2 more answers

A runner increased her distance from 9 miles to 12.5 miles a week. Find the percent increase in mileage.

kondor19780726 [428]

Answer:

<u>39 percent</u> is increase in mileage.

Thus, the correct option is B. 39%.

Step-by-step explanation:

Given:

A runner increased her distance from 9 miles to 12.5 miles a week.

Now, to find percent increase in mileage.

Previous mileage = 9 miles.

Present mileage = 12.5 miles.

<em>Mileage increase = 12.5 - 9 = 3.5 miles.</em>

Now, to get the percent increase in mileage:

$\frac{Mileage\ increased}{previous\ mileage} \times 100$

$=\frac{3.5}{9} \times 100$

$=\frac{350}{9}$

$=38.88\%.$

<u><em>Approximately the percent increase = 39%.</em></u>

Therefore, 39% is increase in mileage.

Thus, the correct option is B. 39%.

4 0

2 years ago