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2 years ago

A smoothie comes in three sizes - small, medium, and large, with five flavors - strawberry, banana,

Mathematics

2 answers:

Ganezh [65]2 years ago

8 0

Hey there! I'm happy to help!

We have three choices for sizes...

And five choices for flavors.

If you choose small, there are 5 smoothies you can make.

With medium, there are also five.

Same with large!

This gives us 15 possible smoothies.

Have a wonderful day! :D

VARVARA [1.3K]2 years ago

3 0

Answer:

A. 15

Step-by-step explanation:

The fundamental counting principle states if there is a outcomes/options and b outcomes/options, the total number of outcomes is a*b.

a * b

There are 3 sizes: small, medium and large

There are 5 flavors: strawberry, banana, orange, blueberry, and watermelon.

Therefore, we can say that a is 3 (sizes) and b is 5 (flavors).

3 * 5

Here is another way to think about it.

You can order a small smoothie five different ways, a medium five different ways, and a large five different ways.

5+5+5=15

Therefore, there are 15 total outcomes and A is correct.

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X + 5 = 29 solve for x : solve for y:

atroni [7]

Answer:

valor de x: 24

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2 years ago

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What is the simplified form of the following expression?

geniusboy [140]

Answer:

242

Step-by-step explanation:

Simplify the following:

11 ((9^2 - 5^2)/2^2 + 8)

Hint: | Evaluate 2^2.

2^2 = 4:

11 ((9^2 - 5^2)/4 + 8)

Hint: | Evaluate 5^2.

5^2 = 25:

11 ((9^2 - 25)/4 + 8)

Hint: | Evaluate 9^2.

9^2 = 81:

11 ((81 - 25)/4 + 8)

Hint: | Subtract 25 from 81.

| 7 | 11

| 8 | 1

- | 2 | 5

| 5 | 6:

11 (56/4 + 8)

Hint: | Reduce 56/4 to lowest terms. Start by finding the GCD of 56 and 4.

The gcd of 56 and 4 is 4, so 56/4 = (4×14)/(4×1) = 4/4×14 = 14:

11 (14 + 8)

Hint: | Evaluate 14 + 8 using long addition.

| 1 |

| 1 | 4

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| 2 | 2:

11×22

Hint: | Multiply 11 and 22 together.

| 2 | 2

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2 | 2 | 0

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Answer: 242

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2 years ago

Please help me! I'll give brainliest!

german

Tan A = BC/AB = 15/8

answer is B. 15/8

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2 years ago

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Harmonic mean if a number h such that (h-a)/(b-h)=a/b Prove h is H(a,b) iff satisfies either relation a. (1/a)-(1/h) = (1/h) - (

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A.

$\displaystyle\frac1a-\frac1h=\frac1h-\frac1b$
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b.

$\displaystyle h=\frac{2ab}{a+b}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{\frac{2ab}{a+b}-a}{b-\frac{2ab}{a+b}}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{2ab-a(a+b)}{b(a+b)-2ab}$
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2 years ago

In the following addition problem, the letters A,B,C stand for three different digits. What digits should replace each letter?

Eva8 [605]

Alright so I got A=4, B=5 and C=9

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2 years ago