Answer:
P(A∣D) = 0.667
Step-by-step explanation:
We are given;
P(A) = 3P(B)
P(D|A) = 0.03
P(D|B) = 0.045
Now, we want to find P(A∣D) which is the posterior probability that a computer comes from factory A when given that it is defective.
Using Bayes' Rule and Law of Total Probability, we will get;
P(A∣D) = [P(A) * P(D|A)]/[(P(A) * P(D|A)) + (P(B) * P(D|B))]
Plugging in the relevant values, we have;
P(A∣D) = [3P(B) * 0.03]/[(3P(B) * 0.03) + (P(B) * 0.045)]
P(A∣D) = [P(B)/P(B)] [0.09]/[0.09 + 0.045]
P(B) will cancel out to give;
P(A∣D) = 0.09/0.135
P(A∣D) = 0.667
Answer: Lshonda will earn $23.
Step-by-step:
The equation would be (4•4.7) + (1•4.2)
4 multiplied by 4.7 is 18.8
1•4.2 is 4.2
18.8+4.2=23
hope this helps! :)
Answer:
- The first option: $265.05
Step-by-step explanation:
<h3>Option 1</h3>
<u>Payment as sequence:</u>
<u>This is an AP with:</u>
- The first term a = 11.75
- Common difference d = 0.35
- Number of terms n = 18
<u>Find the sum of the first 18 terms:</u>
- S₁₈ = (a + a₁₈)*18/2 = (a + a + 17d)*9 = (11.75*2 + 17*0.35)*9 = $265.05
<h3>Option 2</h3>
Flat rate $14.50 per hour
<u>The sum is:</u>
<u>Compared, we see the first option pays more:</u>
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