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Ilia_Sergeevich [38]
3 years ago
8

The solutions to a function are what points on the coordinate plane when you graph the line?​

Mathematics
1 answer:
vodka [1.7K]3 years ago
4 0

The solutions to a function are the points where the graph of the function crosses the x-axis, but only if the solutions are real numbers. If the function has imaginary solutions, then you don't see those on the graph.

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A line passes through the point (6, 7) and has a slope of 4.
8_murik_8 [283]

Answer:

y = 4x - 17

Step-by-step explanation:

we can use the equation y = mx + b

where m is the slope.

now we want to find the value of b.

so

7 = 24 + b

b= -17

so the answer is

y = 4x -17

6 0
1 year ago
Find the distance (-1,-2) and (3,-1)
jasenka [17]

Answer:

\sqrt{17}

Step-by-step explanation:

\sqrt{4^2 + 1^2}

\sqrt{17}

5 0
2 years ago
Use the table to answer the question. X y -21-1 -1 -1 1 0 3 1 5 2 7 Which equation represents the relationship between x and y s
horsena [70]

Answer:

D. y = 2x + 3​

Step-by-step explanation:

Use the table to answer the question.

x:-2  -1   0   1    2

y: -1   1   3   5   7

Which equation represents the relationship between x and y shown in the table.

Solution:

The table shows a linear relationship between x and y.

A linear equation is in the form y = mx + b, where y is a dependent variable, x is an independent variable, m is the rate of change (slope) and b is the value of y when x = 0.

The table (x, y) has the points (-2, -1) and (0, 3). The equation is given by:

y-y_1=\frac{y_2-y_1}{x_2-x_1} (x-x_1)\\\\y-(-1)= \frac{3-(-1)}{0-(-2)} (x-(-2))\\\\y+1=2(x+2)\\\\y+1=2x+4\\\\y=2x+3

5 0
3 years ago
Solve the system of linear equations by substitution 2x-y=6 x=y-1
Oksana_A [137]

substitute x for y-1
2(y-1)-y=6 distribute
2y-2-y=6 subtract y in 2y
y-2=6 add 2 to get y by itself
y=8

Put y back into equation x=y-1
x=8-1
X=7
6 0
3 years ago
What is the center and radius of -10x = -121 - y2 - x2 -22y
OlgaM077 [116]

We need to find the center and the radius of

-10x\: =\: -121\: -\: y^2\: -\: x^2\: -22y

The general circle equation is the following

(x-h)^2+(y-k)^2=r^2

where

(h,k) is the center and

r is the radius

1. rearrange the equation

(x^2-10x)+(y^2+22y+121)=0

2. Add 25 on both sides

(x^2-10x+25)+(y^2+22y+121)=25

3. Factor

(x-5)^2+(y+11)^2=5^2

Now we have an equation that is very similar to the circle equation, so let's compare them

Center -> (h,k) = (5,-11)

radius -> r = 5

8 0
1 year ago
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