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bearhunter [10]
3 years ago
5

Can someone help me on 56,57,59 and 60 plz this will be worth 20 points ASAP

Mathematics
1 answer:
Llana [10]3 years ago
5 0
56) A 57) C 59) B 60) C
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A student said that the relation{(-2,3),(4,4),(4,5),(5, -8)} is a function. Do you agree? Why or why not?
JulijaS [17]

Answer:

Step-by-step explanation:

Disagree.  (4, 4) and (4, 5) show that for a single input, 4, there are two distinct outputs (4 and 5).  In a function no more than 1 output can be associated with a given input.

The given relation is not a function.

5 0
3 years ago
If the graph of y=f(x) passes through the point (0,1), and dy/dx=xsin(x^2)/y, then f(x)= ?
Zigmanuir [339]

The differential equation

d<em>y</em>/d<em>x</em> = <em>x</em> sin(<em>x</em> ²) / <em>y</em>

is separable as

<em>y</em> d<em>y</em> = <em>x</em> sin(<em>x</em> ²) d<em>x</em>

Integrate both sides:

∫ <em>y</em> d<em>y</em> = ∫ <em>x</em> sin(<em>x</em> ²) d<em>x</em>

∫ <em>y</em> d<em>y</em> = 1/2 ∫ 2<em>x</em> sin(<em>x</em> ²) d<em>x</em>

∫ <em>y</em> d<em>y</em> = 1/2 ∫ sin(<em>x</em> ²) d(<em>x</em> ²)

1/2 <em>y</em> ² = -1/2 cos(<em>x</em> ²) + <em>C</em>

Solve for <em>y</em> implicitly:

<em>y</em> ² = -cos(<em>x</em> ²) + <em>C</em>

Given that <em>y</em> = 1 when <em>x</em> = 0, we get

1² = -cos(0²) + <em>C</em>

1 = -cos(0) + <em>C</em>

1 = -1 + <em>C</em>

<em>C</em> = 2

Then the particular solution to the DE is

<em>y</em> ² = 2 - cos(<em>x</em> ²)

Solving explicitly for <em>y</em> would give two solutions,

<em>y</em> = ± √(2 - cos(<em>x</em> ²))

but only the one with the positive square root satisfies the initial condition:

√(2 - cos(0²)) = √1 = 1

-√(2 - cos(0²)) = -√1 = -1 ≠ 1

So the unique solution to this DE is

<em>y</em> = √(2 - cos(<em>x</em> ²))

4 0
2 years ago
He graph shown represents the funds in Sasha's checking account for 16 days.
ss7ja [257]
For the answer to the question above Sasha did not withdraw or deposit any money. (<span>During 5 days of the account balance has not changed).</span> 
I hope my answer helped you. Feel free to ask more questions. Have a nice day!
8 0
3 years ago
Read 2 more answers
Evaluate the expression for a = 5, b = 11, and c = 3. 2a + 2c(b − 5) A. 64 B. 46 C. 54 D. 163
Artemon [7]

2a +2c(b-5)

substitute a=5 b=11 c=3

2(5) +2(3) (11-5)

10+6(6)

10+36

46

Choice B


8 0
3 years ago
Given the set of ordered pairs: {(1,3), (2,7), (x,5), (6,4)}.
MrMuchimi

Answer:

2

Step-by-step explanation:

2 is a value of x that would not make the set a function because a function can't have multiple coordinates wit hthe same domain (x-coordinate). 2 is a domain that has already been used in the point (2,7). If this is used in (x,5), the point would become (2,5) and repeat a domain.

Note:

The x-coordinate could also be 1 or 6 because they have been used as domains as well.

Hope it helps!

8 0
2 years ago
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