Since
![\mathrm M_Y(t)=e^{6(e^t-1}](https://tex.z-dn.net/?f=%5Cmathrm%20M_Y%28t%29%3De%5E%7B6%28e%5Et-1%7D)
, we know that
![Y](https://tex.z-dn.net/?f=Y)
follows a Poisson distribution with parameter
![\lambda=6](https://tex.z-dn.net/?f=%5Clambda%3D6)
.
Now assuming
![\mu,\sigma](https://tex.z-dn.net/?f=%5Cmu%2C%5Csigma)
denote the mean and standard deviation of
![Y](https://tex.z-dn.net/?f=Y)
, respectively, then we know right away that
![\mu=6](https://tex.z-dn.net/?f=%5Cmu%3D6)
and
![\sigma=\sqrt6](https://tex.z-dn.net/?f=%5Csigma%3D%5Csqrt6)
.
So,
The slope of the line that passes through (5, 4) and (-4,3) is ![\frac{1}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9%7D)
<u>Solution:</u>
Given, two points are (5, 4) and (-4, 3)
We have to find the slope of a line that passes through the above given two points.
Slope of a line that pass through
is given as:
![m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx_%7B2%7D-x_%7B1%7D%7D)
![\text { Here, in our problem, } x_{1}=-4, y_{1}=3 \text { and } x_{2}=5, y_{2}=4](https://tex.z-dn.net/?f=%5Ctext%20%7B%20Here%2C%20in%20our%20problem%2C%20%7D%20x_%7B1%7D%3D-4%2C%20y_%7B1%7D%3D3%20%5Ctext%20%7B%20and%20%7D%20x_%7B2%7D%3D5%2C%20y_%7B2%7D%3D4)
![\text { slope } m=\frac{4-3}{5-(-4)}=\frac{1}{5+4}=\frac{1}{9}](https://tex.z-dn.net/?f=%5Ctext%20%7B%20slope%20%7D%20m%3D%5Cfrac%7B4-3%7D%7B5-%28-4%29%7D%3D%5Cfrac%7B1%7D%7B5%2B4%7D%3D%5Cfrac%7B1%7D%7B9%7D)
Hence, the slope the line that passes through the given points is ![\frac{1}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9%7D)
The first option and the last option :)
Answer:
Well add the first numbers and get 10.34 you can add up to at least 5 to 6 toppings.
Step-by-step explanation: